Answer:
0.5798 or 57.98%
Step-by-step explanation:
The total number of ways to form the two teams is the combination of choosing 10 people out of 35 (₃₅C₁₀). The number of possibilities that A and B are both on the 10-people team is given by the combination of choosing 8 people (since two are fixed) out of 33 (₃₃C₈).The number of possibilities that A and B are both on the 25-people team is given by the combination of choosing 10 people out of 33 (₃₃C₈).
Therefore, the probability that two particular people A and B will be on the same team is:
The probability is 0.5798 or 57.98%.
Convert any mixed numbers to fractions.
Then your initial equation becomes:
15
4
×
4
1
Applying the fractions formula for multiplication,
=
15
×
4
4
×
1
=
60
4
Simplifying 60/4, the answer is
15
Answer:
C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.
Step-by-step explanation:
Let μ be the the average attendance at games of the football team
The claim: the average attendance at games is over 523
Null and alternative hypotheses are:
: μ=523
: μ>523
The conclusion is failure to reject the null hypothesis.
This means that <em>test statistic</em> is lower than <em>critical value</em>. Therefore it is not significant, there is no significant evidence to accept the <em>alternative</em> hypothesis.
That is no significant evidence that the average attendance at games of the football team is greater than 523.
<span>Find an equation for the line parallel to 2y+4x = 8 and goes through the point (-3,3). Write your answer in the form y=mx+b.</span>
(2x+3)+(x-6)= 180 [straight angle]
2x+x+3-6=180
3x=183
x=61
(All measure in degree)
Hope this can help.
