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vfiekz [6]
3 years ago
11

(20 points will get brainliest)

Mathematics
2 answers:
Nina [5.8K]3 years ago
8 0

Answer:

y(x)=19*x

Step-by-step explanation:

Given the height of <em>6 </em>DVD cases, you can know the height of a <em>single</em> DVD case, by dividing the total height, in the number of cases (\frac{114mm}{6} = 19mm for this problem).

Now, knowing the height of a <em>single</em> DVD case (19mm), you can think the expression in this way: <em>If I already know the height of a single case, the height of any number of cases will be the result of multiplying the height of the case by the number of cases I want to stack.</em>

As the problem states, x is the number of cases in the stack, so, multiply the height of a single case for the number of cases (x).

This will result in the expression: y(x)=19*x

To know the height of a stack of 13 cases, just replace x=13 in the equation you just figured:  y(13)= 19* (13) = 247 , but don't forget the unit is mm, so the final result is <u>247 </u><u><em>mm.</em></u>

Mama L [17]3 years ago
4 0
Y = 19x

The height of 13 would be 247mm
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lisov135 [29]

Answer:

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that \mu = 0, \sigma = 1

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

Z = \frac{X - \mu}{\sigma}

Z = \frac{-1.69 - 0}{1}

Z = -1.69

Z = -1.69 has a p-value of 0.0455

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Z = \frac{X - \mu}{\sigma}

Z = \frac{-2.23 - 0}{1}

Z = -2.23

Z = -2.23 has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

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3 years ago
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