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pickupchik [31]
3 years ago
6

Finch divides 12 peaches and 18 Nectarines into the same number of equal groups. How many possible groups of each fruit can he m

ake? How many are in each group?
Mathematics
1 answer:
Naya [18.7K]3 years ago
7 0

This question is based on prime factorization method.

As given there are 12 peaches and 18 nectarines

Factors of 12 are : 2,3,4,6 and 12

Factors of 18 are : 2,3,6,9 and 18

As mentioned, fruits are divided into the same number of equal groups, so the groups can be formed as-

1. 6 groups of peaches with 2 in each and 6 groups of nectarines with 3 in each,

2. 3 groups of peaches with 4 in each and 3 groups of nectarines with 6 in each.

3. 2 groups of peaches with 6 in each and 2 groups of nectarines with 9 in each.




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4. Use the process outlined in the lesson to approximate the number 2√3. Use the approximation √3 ≈ 1.732 050 8.
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Answer:

sequence of five intervals

(1) 2  < 2^{\sqrt{3} }   < 2^{2}

(2) 2^{1.7}  < 2^{\sqrt{3} }    < 2^{1.8}

(3) 2^{1.73}  < 2^{\sqrt{3} }    < 2^{1.74}

(4) 2^{1.732}  < 2^{\sqrt{3} }    < 2^{1.733}

(5) 2^{1.7320}  < 2^{\sqrt{3} }    < 2^{1.7321}

Step-by-step explanation:

as per question given data      

√3 ≈ 1.732 050 8 

to find out      

sequence of five intervals

solution      

as we have given that √3 value that is here

√3 ≈ 1.732 050 8            ........................1

so  

when we find 2^{\sqrt{3} }           ................2

put here √3 value in equation number  2  

we get  2^{\sqrt{3} }   that is  3.322    

so    

sequence of five intervals

(1) 2  < 2^{\sqrt{3} }   < 2^{2}

(2) 2^{1.7}  < 2^{\sqrt{3} }    < 2^{1.8}

(3) 2^{1.73}  < 2^{\sqrt{3} }    < 2^{1.74}

(4) 2^{1.732}  < 2^{\sqrt{3} }    < 2^{1.733}

(5) 2^{1.7320}  < 2^{\sqrt{3} }    < 2^{1.7321}

8 0
3 years ago
Four divided by what equals 195
ella [17]
Well, you would need to do 195x4 and you would get 780, I believe. So 780 divided by 4 is 195.
7 0
3 years ago
Read 2 more answers
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