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3 years ago

HELP ME PLEASE 25 points

Mathematics

2 answers:

Aleks04 [339]3 years ago

8 0

Hello,

1) 2<2&2/3=2.6666...<3 Answer C (2 and 3)

2)-4<-3.75<3 Answer B ( A and B)

3)abs(B)=3/8 Answer B

4)an absolue value is always positive or null answer FALSE

5)|5-9|=|-4|=4 answer C

6)-|5|+|-5|=-5+5=0 answer C

7)I have understand AC as distance between A and C =2

AC-EF=2-1=1 Answer C

8) CF=2-(-2)=4 Answer D

9) NE=5-1=4 answer C

10)
x-7=6
==>x=1
Answer A

ira [324]3 years ago

7 0

Pg1
1. f,g
2. a,b
3. 3/8
pg2
1 false
2 -4
3 -10
4 -5
pg 3
1 0
2 6
3 13

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Form a sequence that has two arithmetic means between -1 and 59.

9966 [12]

Answer:

Correct choice is B

Step-by-step explanation:

For the numbers -1 and 59, find the difference 59-(-1):

since 59-(-1)=60 and $\dfrac{60}{3}=20$ (two arithmetic means tells you there will be three intervals), two arithmetic means will be

-1+20=19;
19+20=39.

The only correct sequence is -1, 19, 39, 59.

7 0

3 years ago

Read 2 more answers

Round 5,267.82 to the nearest ten

LiRa [457]

5,270 is 5,267.82 rounded to the nearest ten
hope this helps

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3 years ago

Find the sum of 10x^2-10x-6 and x+6.

Andre45 [30]

Answer:

10x²−9x

Step-by-step explanation:

10x²−10x−6+x+6

=10x²−10x−6+x+6

Combine Like Terms:

=10x²−10x−6+x+6

=(10x²)+(−10x+x)+(−6+6)

=10x²−9x

Hope this helps!

3 0

3 years ago

A Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer; a sample

8090 [49]

Answer:

Step-by-step explanation:

Step(i):-

Given first random sample size n₁ = 500

Given Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer.

First sample proportion

$p^{-} _{1} = \frac{65}{500} = 0.13$

Given second sample size n₂ = 700

Given a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer.

second sample proportion

$p^{-} _{2} = \frac{133}{700} = 0.19$

Level of significance = α = 0.05

critical value = 1.96

Step(ii):-

Null hypothesis : H₀: There is no significance difference between these proportions

Alternative Hypothesis :H₁: There is significance difference between these proportions

Test statistic

$Z = \frac{p_{1} ^{-}-p^{-} _{2} }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }$

where

$P = \frac{n_{1} p^{-} _{1}+n_{2} p^{-} _{2} }{n_{1}+ n_{2} } = \frac{500 X 0.13+700 X0.19 }{500 + 700 } = 0.165$

Q = 1 - P = 1 - 0.165 = 0.835

$Z = \frac{0.13-0.19 }{\sqrt{0.165 X0.835(\frac{1}{500 } +\frac{1}{700 } )} }$

Z = -2.76

|Z| = |-2.76| = 2.76 > 1.96 at 0.05 level of significance

Null hypothesis is rejected at 0.05 level of significance

Alternative hypothesis is accepted at 0.05 level of significance

Conclusion:-

There is there is a difference between these proportions at α = 0.05

3 0

3 years ago

What is the solution to the equation below?

Bess [88]

W=2/12 you just divide both sides by 4

5 0

3 years ago