D = sqrt(3s^2) where s is the length of the side. Solving for s,
<span>3s^2 = d^2 iff </span>
<span>s^2 = d^2 / 3 iff </span>
<span>s = sqrt(d^2 / 3) </span>
<span>= d / sqrt(3) or d sqrt(3) / 3 </span>
<span>Surface area of the cube = 6 s^2. Thus, </span>
<span>A = 6 (d / sqrt(3))^2 </span>
<span>= 6d^2 / 3 </span>
<span>= 2d^2 </span>
<span>Volume = s^3. Thus, </span>
<span>V = (d / sqrt(3))^3 </span>
<span>= d^3 / 3sqrt(3) </span>
<span>= d^3 sqrt(3) / 9</span>
Answer:
let me take a guess and if its wrong sorry
Step-by-step explanation:
12
Answer:
i dont know i think it is 11?!? srry if im wrong
Step-by-step explanation:
Answer:
Step-by-step explanation:
Both triangles are shown are similar. Therefore, the ratio of their sides will be maintained. We can then set up the following proportion:
Yes. When solving a problem like this, multiply the base numbers normally, and add the exponents together.
If you need more help, comment below and I'd be happy to assist.
