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vladimir2022 [97]
3 years ago
12

The average time for 100-meter race that Usain Bolt used is 9.6 seconds on average. He wants to test whether his speed has decre

ased or not. His speed was tested for 16 times, and the average time is 9.7 seconds. Assume the population standard deviation is 0.1 second. At a 5% significance level, the decision is to _________.
Mathematics
1 answer:
Fantom [35]3 years ago
7 0

Answer:

At a 5% significance level we reject the Null hypothesis H_0

Step-by-step explanation:

From the question we are told that:

Distance d= 100

Mean \mu=9.6

Sample size n=16

Sample mean \=x=9.7

Standard deviation \sigma= 0.1

significance level \alpha=5%=>0.05

Generally the Hypothesis is mathematically given by

 H_0=\mu=9.6

 H_a=\mu=9.6

Generally the equation for t test statistics is mathematically given by

 t=\frac{\=x-\mu}{\frac{\sigma}{\sqrt{n} } }

 t=\frac{9.7-9.6}{\frac{0.1}{\sqrt{16} } }

 t=4

Therefore P-Value from table

 P-Value=0.000

 \alpha>P-value

Therefore

At a 5% significance level we reject the Null hypothesis H_0

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alexandr1967 [171]
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1,1
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4 years ago
The points (-7,-1) and (-8,6) fall on a particular line. What is its equation in point-slope form?
Arisa [49]

Answer:

y - 6 = -7(x + 8)

Step-by-step explanation:

Slope: m = (y2-y1)/(x2-x1) = (6 - -1)/(-8 - -7) = (6 + 1)/(-8 + 7) = 7/-1 = -7

Point-slope form: y - 6 = -7(x - -8)

=> y - 6 = -7(x + 8)

3 0
3 years ago
Find the measure of the following angles given
olga55 [171]

Answer:

Step-by-step explanation:

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m∠6 = 130

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m∠15 = 65

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3 years ago
Nadine walked 1⁄4 of a mile, Janet walked 3⁄8 of a mile, and Perry walked 5⁄6 of a mile. Who walked the farthest? How much farth
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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The lifetime of a computer can be modeled by an exponential random variable with an expected lifetime of 900 days. 1. Find the p
weeeeeb [17]

Answer:

1.  0.108368

2. 0.188876

Step-by-step explanation:

Let X be the exponential random variable that represents the lifetime of a computer.

i.e. X\sim Exp(0.001)

The probability that the computer will function more than 2000 days can be computed as follows:

P(X > 2000)

: f_X(x) = \lambda e^{-\lambda x

P(X > 2000) = 1  - P(X< 2000)

P(X > 2000) = exp(-2000/β) = e⁻²²

P(X > 2000) = 0.108368

2.

By applying conditional probability;

P(X>2000 \bigg | X>500) =\dfrac{P(X>2000 \  \cap  \ X>500)}{P(X> 500)}

P(X>2000 \bigg | X>500) =\dfrac{P(X>2000 )}{P(X> 500)}

P(X>2000 \bigg | X>500) =\dfrac{0.108368 }{0.57375}

\mathbf{P(X>2000 \bigg | X>500) =0.188876}

7 0
3 years ago
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