A family drove to their grandmother's house after the average 200 miles per day

1 rectangle has a circumference of 72cm. If you reduce the width by 6cm and keep the same length, the area will decrease by 120c

WARRIOR [948]

Answer

the length is 20 cm and breadth is 16cm

Step-by-step explanation:

let, 2(a+b)= 72( as its the formulae of circumference)

here a is the length and b is the breadth

now total area is ab

according to the question

a(b-6)= ab-120

or -6a= - 120

so length is 20 cm

now by putting the value in the 1st eq we get

2(a+b)=72

or(a+b)=36

or 20+b=36

so breadth is 16 cm.

length is 20cm and breadth is 16 cm

(u can verify that easily)

thank u

5 0

2 years ago

F(x)=x-1/x^2-x-6 which is the graph of

hoa [83]

Answer:

The graph is attached below.

Step-by-step explanation:

<em>As you have not added the graph, so I will be solving the function for a graph.</em>

Given the function

$f\left(x\right)=x-\frac{1}{x^2}-x-6$

$x-\mathrm{axis\:interception\:points\:of\:}-\frac{1}{x^2}-6:$

$\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0$

$-\frac{1}{x^2}-6=0$

$-1-6x^2=0$

$\mathrm{No\:Solution\:for}\:x\in \mathbb{R}$

$\mathrm{No\:x-axis\:interception\:points}$

$y-\mathrm{axis\:interception\:point\:of\:}-\frac{1}{x^2}-6:$

$y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0$

As we know that the domain of a function is the set of input or argument values for which the function is real and defined.

$\mathrm{Domain\:of\:}\:-\frac{1}{x^2}-6\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-\infty \:,\:0\right)\cup \left(0,\:\infty \:\right)\end{bmatrix}$

$\mathrm{Since}\:x=0\:\mathrm{is\:not\:in\:domain}$

$\mathrm{No\:y-axis\:interception\:point}$

$\mathrm{Asymptotes\:of}\:-\frac{1}{x^2}-6:\quad \mathrm{Vertical}:\:x=0,\:\mathrm{Horizontal}:\:y=-6$

$\mathrm{Range\:of\:}-\frac{1}{x^2}-6:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)$

The graph is attached below.

5 0

3 years ago

A car passes a landmark on a highway traveling at a constant rate of 40 kilometers per hour. Two hours later, a second car passe

Ratling [72]

So first you want to find how much the second car gains on the first car in one hour.

Since the second car travels 65 kph, but the first travels 40, we can just subtract 40 from 65 to find how much faster the second car is than the first.

65 - 40 = 25

So the second car is 25 kph faster than the first.

Since the first car had a 2 hour head start, we first want to calculate how far away the first car got from the sign before the second car reached the sign.

So just 2 hours * 40 kph, which gives you 80 kilometers.

So now we know the second car has to gain 80 km on the first car in order to overtake it.

Since the second car gains 25 km per hour on the first car, we can just divide 80 by 25.

80 / 25 = 16/5, or in decimal form 3.2.

So the second car will overtake the first car in 3.2 hours, or 192 minutes, which is also 3 hours and 12 minutes.

3 0

3 years ago

Read 2 more answers

I NEED HELP ON THIS PLEASE SOMEBODY PLEASE JUST GIVE ME THE RIGHT ANSWER.

ella [17]

Answer: I am pretty sure it is 300. If it is not my bad But I am pretty sure it is.

Step-by-step explanation: I worked it out.

7 0

2 years ago

True or false: f(x) is a function

Lostsunrise [7]

False because 5 is associated with two values.