Answer:
<em>Area</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>garden</em><em>=</em><em>1</em><em>2</em><em>1</em><em> </em><em>square</em><em> </em><em>meter</em>
<em>perimeter</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>garden</em><em>=</em><em>4</em><em>4</em><em> </em><em>meter</em>
Step-by-step explanation:
Area of a square=side*side
=11*11
=<u>1</u><u>2</u><u>1</u><em><u>s</u></em><em><u>q</u></em><em><u>u</u></em><em><u>a</u></em><em><u>r</u></em><em><u>e</u></em><em><u> </u></em><em><u>meter</u></em>
Perimeter of a square garden=side*4
=11*4
=44 m
For every x input, hours, the y output, distance is multiplied by a factor of 3. So 1-3. (3, 9) and (5,15) and then to graph those points fine the corresponding x and y values and put a point there
Generally speaking... yes! It is possible. It would just have to be less than 90 degrees to be considered acute.
That wouldn't be very comfortable for the horse.
Slope = (4 - 0)/(0 - 8) = -1/2
b = 4
equation
y = 1/2(x) + 4
Answer:
Ok so the answer to this question is 1/6
Step-by-step explanation:
Since there is 6 boxes and only one of them is lit up It would equal to 1/6
Hope it helps!!
