Question

a pyramid has a volume of 1944 in and a rectangular base with the dimensions of 18 and 9 in what is the height of the pyramid​

Answer 1

Answer:

The height is 36 in

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, a rectangular based pyramid.

Step one

Given data

Volume v =  1944 in

length of base l =  18 in

width of base w = 9 in

Height h=   ?

Step two

we know that the expression for the volume of a pyramid is given as

$volume=\frac{ lwh}{3}$

substituting our given data we have

$volume = \frac{18*9*h}{3} \\volume = \frac{162h}{3} \\volume= 54h$

but volume = 1944 in therefore

$1944= 54h\\h= \frac{1944}{54} \\h= 36 in$