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olga nikolaevna [1]
3 years ago
5

HELPPPPO THIS IS DUE TOMORROW!

Mathematics
1 answer:
Leviafan [203]3 years ago
4 0
Here you go love. I worked out the problem and showed the word answers :)

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What is the simplified form of 5 - 4y + 2x - 3y - 2 + 5x?
leva [86]
Combine like terms.

5-2=3

-4y-3y=-7y

2x+5x=7x

Put these combined values together:
3-7y+7x

Final answer: A
7 0
3 years ago
10(-9X8+1,450,395X-50-1.304)
jasenka [17]

Answer:

9

Step-by-step explanation:

5 0
2 years ago
Solve the equation for x. 2x + 22 = 4(x+3)
shusha [124]

Answer:

x = 5

Step-by-step explanation:

We have the algebraic expression and are asked to solve for x.

To solve, we need to isolate x.

2x + 22 = 4(x + 3)

Distribute :

2x + 22 = (4(x) + 4(3))

2x + 22 = 4x + 12

Subtract 12 from both sides :

2x + 10 = 4x

4x = 2x + 10

Subtract 2x from both sides :

2x = 10

Divide 2 from both sides to get x alone :

x = 5

5 0
3 years ago
Read 2 more answers
Complete the equation of the line through (-8,-2)(-4,6)<br> use exact numbers
Firdavs [7]

Answer:

y = 2x + 14

Step-by-step explanation:

Hope this helps!!!

First, you have to find the slope by using

In other words,

The slope is 2.

Then you plug the rest into point-slope form (you can use either of the points, I used the first one)

Remember that m is the slope.

Distribute the slope to the parenthesis

Isolate the y variable

6 0
3 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
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