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bija089 [108]
3 years ago
6

The vertex of the parabola below is at the point (-4,-2) wich of the equations below could be the one for this parabola

Mathematics
2 answers:
Eva8 [605]3 years ago
7 0

Answer:

X= -2(y+2)^2-4

Step-by-step explanation:


MrRissso [65]3 years ago
6 0

The parabola with with a vertex at (-4,-2) represents any member of parabolas with the equation y(x)=a(x+4)^2-2 where a is any real number with the exception that  a\neq 0.

The reason any equation  of the form y(x)=a(x+4)^2-2 works is that there are an infinite number of parabolas with a vertex at (-4,-2). All of these parabolas are formed by applying some transformation that involves a vertical translation of -2 and a horizontal translation of -4 on the parabola y=x^2. The different variations are archived by varying the constant a.  When a is negative, the parabolas will face downwards. When a is negative, the parabolas will be face downwards.

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Answer:

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Step-by-step explanation:

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3 years ago
Can someone help please?
Katarina [22]

Answer:

g = 6

Step-by-step explanation:

<em>To find the slope you do:</em>

m = change in y ÷ change in x or (y2 - y1) ÷ (x2 - x1)

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<em>Sub in the values:</em>

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2 = (4) ÷ (g - 4)

4 divided by what gives us 2? 2. This means that g - 4 = 2, g = 2 + 4 which is 6:

g = 6

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