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3 years ago

8

The freezing point of helium is -468 degrees Fahrenheit. If you increase that temperature by 569.7 degrees Fahrenheit, you reach

the freezing point of phosphorus. What is the freezing point of phosphorus?

1 answer:

balandron [24]3 years ago

3 0

The answer to your question would be that 101.7 is the freezing point of phosphorous.

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Question 4 <br> Use the figure below to find the value of x and y

Tpy6a [65]

Answer:

$x=4, y=8$

Step-by-step explanation:

step 1

Find the value of y

we know that

In the right triangle of the figure

$cos(30\°)=\frac{4\sqrt{3}}{y}$

Remember that

$cos(30\°)=\frac{\sqrt{3}}{2}$

so

$\frac{\sqrt{3}}{2}=\frac{4\sqrt{3}}{y}$

Simplify

$y=8\ units$

step 2

Find the value of x

In the right triangle of the figure

$sin(30\°)=\frac{x}{8}$

Remember that

$sin(30\°)=\frac{1}{2}$

so

$\frac{1}{2}=\frac{x}{8}$

$x=4\ units$

4 0

3 years ago

What is the slope of the graphed function?

Aleonysh [2.5K]

The slope is -1 as picking any two points, and finding (y2-y1)/(x2-x1)=-1

4 0

3 years ago

In an arithmetic sequence, the nth term an is given by the formula an=a1+(n−1)d, where a1 is the first term and d is the commo

Dmitry_Shevchenko [17]

Answer:

$a_{10} = \frac{10}{65536}$

Step-by-step explanation:

The first step to solving this problem is verifying if this sequence is an arithmetic sequence or a geometric sequence.

This sequence is arithmetic if:

$a_{3} - a_{2} = a_{2} - a_{1}$

We have that:

$a_{3} = 40, a_{2} = 10, a_{3} = \frac{5}{2}$

$a_{3} - a_{2} = a_{2} - a_{1}$

$\frac{5}{2} - 10 = 10 - 40$

$\frac{-15}{2} \neq -30$

This is not an arithmetic sequence.

This sequence is geometric if:

$\frac{a_{3}}{a_{2}} = \frac{a_{2}}{a_{1}}$

$\frac{\frac{5}[2}}{10} = \frac{10}{40}$

$\frac{5}{20} = \frac{1}{4}$

$\frac{1}{4} = \frac{1}{4}$

This is a geometric sequence, in which:

The first term is 40, so $a_{1} = 40$

The common ratio is $\frac{1}{4}$ , so $r = \frac{1}{4}$ .

We have that:

$a_{n} = a_{1}*r^{n-1}$

The 10th term is $a_{10}$ . So:

$a_{10} = a_{1}*r^{9}$

$a_{10} = 40*(\frac{1}{4})^{9}$

$a_{10} = \frac{40}{262144}$

Simplifying by 4, we have:

$a_{10} = \frac{10}{65536}$

3 0

3 years ago

Help find the distance between two points?

miv72 [106K]

Answer:

4

Step-by-step explanation:

Calculate the distance using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = B(0, 0) and (x₂, y₂ ) = ( $\frac{\sqrt{6} }{2}$ , $\frac{\sqrt{58} }{2}$ )

AB = $\sqrt{((\frac{\sqrt{6} }{2})^2 }$ + $\{(\frac{\sqrt{58} }{2})^2 }$

= $\sqrt{\frac{6}{4} }$ + $\frac{58}{4}$

= $\sqrt{\frac{64}{4} }$

= $\sqrt{16}$

= 4

7 0

3 years ago

The set of ordered pairs (–1, 8), (0, 3), (1, –2), and (2, –7) represent a function. What is the range of the function? {x: x =

Alex Ar [27]

{y: y= -7, -2, 3, 8} is the range of the function.

6 0

3 years ago

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