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katrin2010 [14]
3 years ago
7

Help me with this and give the correct answer and get 25 points

Mathematics
2 answers:
love history [14]3 years ago
7 0

Answer:

x =6.0

The base is 6x  = 35.8

The side is 3x =  17.9

Step-by-step explanation:

We can use the pythagorean theorem

a^2 + b^2 = c^2

(6x)^2 +(3x)^2 = 40^2

36x^2 + 9x^2 = 1600

Combine like terms

45x^2 = 1600

Divide each side by 45

45x^2 /45 =1600/45

x^2 =35.555555555

Take the square root of each side

sqrt(x^2) = sqrt(35.555555555)

x =5.96284794 = 6.0

The base is 6x = 6*5.9628479 =35.77708 = 35.8

The side is 3x = 3*5.9628479 =17.88854382= 17.9

yulyashka [42]3 years ago
3 0

Answer:

x = 6.0

3x = 17.9

6x = 35.8

Step-by-step explanation:

Using pythagoras theorem

40² = (3x)² + (6x)²

1600 = 9x² + 36x²

1600 = 45x²

x² = 320/9

x = 5.96284794

3x = 17.88854382

6x = 35.77708764

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Write the first six terms of the geometric sequence with the first term 6 and common ratio 1/3
Alja [10]

Answer:

6, 2, 2/3, 2/9, 2/27, 2/81

Step-by-step explanation:

The nth term of a geometric progression is expressed as;

Tn  = ar^n-1

a is the first term

n is the number of terms

r is the common ratio

Given

a = 6

r = 1/3

when n = 1

T1 = 6(1/3)^1-1

T1 = 6(1/3)^0

T1 = 6

when n = 2

T2= 6(1/3)^2-1

T2= 6(1/3)^1

T2 = 2

when n = 3

T3 = 6(1/3)^3-1

T3= 6(1/3)^2

T3= 6 * 1/9

T3 = 2/3

when n = 4

T4 = 6(1/3)^4-1

T4= 6(1/3)^3

T4= 6 * 1/27

T4 = 2/9

when n = 5

T5 = 6(1/3)^5-1

T5= 6(1/3)^4

T5= 6 * 1/81

T5 = 2/27

when n = 6

T6 = 6(1/3)^6-1

T6= 6(1/3)^5

T6= 6 * 1/243

T6 = 2/81

Hence the first six terms are 6, 2, 2/3, 2/9, 2/27, 2/81

6 0
2 years ago
The functions f and g are defined as follows f(x)=5x+3/6x+7 and g(x)= square root sign x^2-4x
telo118 [61]
<span>f(x)=5x+3/6x+7

This means that f(6/x) = [</span>5(6/x)+3] / [6(6/x)+7] = [ 30/x +3 ] / [36/x +7]

If we assume x≠0 ,    f(6/x) = [30 +3x]/ [36 + 7x]

g(x)=√<span> [ x^2-4x ]
</span>
g(x-4) = √ [ (x-4)^2-4(x-4) ] = √ [ x² -8x +16 -4x +16 ] = √ [ x^2-12x +32]
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2 years ago
In how many ways can 7 people line if A needs to be first or last and B needs to be in the middle
12345 [234]

Answer:

<em>Assuming person A and person B are part of the 7 people</em>, there are 10 ways the 7 people can line up if A needs to be first or last and B needs to be in the middle.

Step-by-step explanation:

There are 2 places for A (first, last) and 5 places for B (anywhere but first or last). 2 x 5 = 10.

8 0
2 years ago
A teacher can grade 25 papers in 4 hours. How many papers can he grade in 6 hours?
lianna [129]
6hours(25papers/hour)=150 papers

6 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!
Semmy [17]
You should put 4 as x, -3 as y and a as slope to make an equation :
- 3 =  a \times 4
then you can find the slope and the correct equation of the line :

the slope is :
- 3 = 4a \\ a =  \frac{ - 3}{4}
so the equation of the line will be
y =  \frac{ - 3}{4}  x
D is true
hope this helps
5 0
3 years ago
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