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kompoz [17]
3 years ago
6

In how many ways can 7 people line if A needs to be first or last and B needs to be in the middle

Mathematics
1 answer:
12345 [234]3 years ago
8 0

Answer:

<em>Assuming person A and person B are part of the 7 people</em>, there are 10 ways the 7 people can line up if A needs to be first or last and B needs to be in the middle.

Step-by-step explanation:

There are 2 places for A (first, last) and 5 places for B (anywhere but first or last). 2 x 5 = 10.

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How much power is used if a force of 35 newtons is used to push a box a distance of 20 meters in 5 seconds
Umnica [9.8K]

Answer:

140 W

Step-by-step explanation:

Power is measured in joules per second, or watts. A joule is a measure of energy equal to 1 newton-meter. These unit relationships tell you how to combine the numbers:

power = (35 N)(20 m)/(5 s) = (35·20/5) N·m/s = 140 J/s = 140 W

6 0
3 years ago
Consider this expression.(The square root of a to the power of 3 - 7 )+ lbl When a = 2 and b = -4, the value of the expression i
lesya692 [45]

Given that: a = 2, b = -4

\sqrt{a^3-7}\text{ + |b| = }\sqrt{2^3-7}\text{ + |-4| = }\sqrt{8-7}\text{ }+\text{ 4 = }\sqrt{1}+\text{ 4 = 1 + 4 = 5}

3 0
1 year ago
Find the slope of the line that passes through the points (2.1) and (-1.-1).​
sp2606 [1]

Answer: The slope is \frac{2}{3}

Step-by-step explanation:

The slope can be calculated with the following formula:

m=\frac{y_2-y_1}{x_2-x_1}

Then, knowing that the line passes through the points (2,1) and (-1,-1), we can substitute the coordinates into the formula.

In this case:

y_2=-1\\y_1=1\\x_2=-1\\x_1=2

Therefore, the slope of the line that passes through the points (2,1) and (-1,-1) is:

m=\frac{-1-1}{-1-2}\\\\m=\frac{-2}{-3}\\\\m=\frac{2}{3}

6 0
3 years ago
Critical Thinking: Empirical/Quantitative Skills
aliya0001 [1]

Answer:

1. 0.0910 = 9.10% probability that exactly 180 passengers show up for the flight.

2. 0.4522 = 45.22% probability that at most 180 passengers show up for the flight.

3. 0.5478 = 54.78% probability that more than 180 passengers show up for the flight.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

Assume that there is a 0.905 probability that a passenger with a ticket will show up for the  flight.

This means that p = 0.905

Also assume that the airline sells 200 tickets

This means that n = 200

Question 1:

Exactly, so we can use the P(X = x) formula, to find P(X = 180).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 180) = C_{200,180}.(0.905)^{180}.(0.095)^{20} = 0.0910

0.0910 = 9.10% probability that exactly 180 passengers show up for the flight.

2. When 200 tickets are sold, calculate the probability that at most 180 passengers show up for the flight.

Now we have to use the approximation.

Mean and standard deviation:

\mu = E(X) = np = 200*0.905 = 181

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{200*0.905*0.095} = 4.15

Using continuity correction, this is P(X \leq 180 + 0.5) = P(X \leq 180.5), which is the p-value of Z when X = 180.5. Thus

Z = \frac{X - \mu}{\sigma}

Z = \frac{180.5 - 181}{4.15}

Z = -0.12

Z = -0.12 has a p-value of 0.4522.

0.4522 = 45.22% probability that at most 180 passengers show up for the flight.

3. When 200 tickets are sold, calculate the probability that more than 180 passengers show up for the flight.

Complementary event with at most 180 passengers showing up, which means that the sum of these probabilities is 1. So

p + 0.4522 = 1

p = 1 - 0.4522 = 0.5478

0.5478 = 54.78% probability that more than 180 passengers show up for the flight.

4 0
2 years ago
-2(3x-4)=4(5x-11) Solve for x
sveta [45]

-2(3x-4)=4(5x-11)

-6x+8=20x-44

8+44=26x

26x=52

x=52/26

your answer will be x=2

6 0
3 years ago
Read 2 more answers
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