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kompoz [17]
3 years ago
6

In how many ways can 7 people line if A needs to be first or last and B needs to be in the middle

Mathematics
1 answer:
12345 [234]3 years ago
8 0

Answer:

<em>Assuming person A and person B are part of the 7 people</em>, there are 10 ways the 7 people can line up if A needs to be first or last and B needs to be in the middle.

Step-by-step explanation:

There are 2 places for A (first, last) and 5 places for B (anywhere but first or last). 2 x 5 = 10.

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Which of the graphs below represents the equation 8x - y = -4?
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4 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!! PLEASE SHOW YOUR WORK!
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Simplify:

Solution ===>  −7      +     12    −     3(50    −    4(2     +      3))   =========>      -85

=       5       −         3(50        −     4(2      +     3))

=        5       −       3(50      −       (4)(5))

=        5        −     3(50     −     20)

=        5       −        (3)(30)

=        5      −      90

=               −85

Answer   ================>         -85









Simplify:

1/3   +   6(2/3     -      1/6)^2

1/3    +     6(1/2)^2

1/3     +    6(1/4)

1/3     +      3/2

Answer    =======>    11/6   =========>      Decimal  =======>    1.833333.....






Hope that helps!!!!                                                         : )



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