(I)1.272727... = 14/11
(II)0.1282828...= 127/990
(The solution is in the picture
NB : the two points on the two numbers in the solution means those two numbers are recurring or repeating )
Answer:
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Step-by-step explanation:
Answer:
Results:
0.1432
0.0045
0.0905
0.0483
Step-by-step explanation:
Step a:
P(A or 10, A or 10) = 20/52 * 19/51 = 5/13 / 19/51 = 95/663 = 0.1432
Step b:
P(A A) = 4/52 * 3/51 = 1/13 * 1/17 = 1/221 = 0.0045
Step c:
P(10 10) = 16/52 * 15/51 = 4/13 * 5/17 = 20/221 = 0.0905
Step d:
P(A 10 or 10 A) = 2 * 4/52 * 16/51 = 2/13 * 16/51 = 32/663 = 0.0483
As well we get the probability by subtracting a, b and c:
P(blackjack): 0.1432 - 0.0905 - 0.0045 = 0.0482
When you reflect across the y axis the y coordinate stays the same and the x coorrdinate changes sign so x = -1 goes to x = 1
Answer point B is (1,6)
