<span>Some equivalent fractions of 4/15 are: 8/30 = 12/45 = 16/60 = 20/75 = 24/90 Hope this helps</span>
The perimeter is
P = 2w + 2l
the rectangular table is 5 inches longer than the width
P = 2w + 2(w + 5)
now we can use that to solve
P = 2w + 2w + 10
P = 4w + 10
P > 92
10 + 4w > 92
subtract 10 from both sides
4w > 82
Divide both sides by 4
w > 20.5
The width can be greater than or equal to 20.50 inches.
Hope this helps :)
Answer:
30
Step-by-step explanation:
You take a protractor and put at c then you measure
Since it's not mentioned I assume the Event of tossing a die twice are done simultaneously.
1- What is the theoretical probability that a coin toss results in two heads showing? I guess you mean: The theoretical probability of tossing 2 heads in 2 flips, if so P(1st Head) = 1/2 AND P(2nd Head) = 1/2, then the probability of getting 2 heads simultaneously is P(1st Head AND 2nd Head) = 1/2 x 1/2 = 1/4
2- What is the experimental probability that a coin toss results in two heads showing? In this case, I suggest that you toss a coin several times until 2 heads appear and then you calculate P: Assuming you get 2 heads (out of 10toss), the P(H) =2/10
3- What is the experimental probability that a coin toss results in two tails showing? Same logic as the previous one
4- What is the theoretical probability that a coin toss results in one head and one tail showing? If you get one Head, P(H) =1/2 and if you want a tail in the 2nd toss P(1/2). So P(one Head AND one tail) = 1/2 x 1/2 = 1/4
5- What is the experimental probability that a coin toss results in one head and one tail showing? Same as 3- or 4-
Answer:
30
Step-by-step explanation:
40- 10 equals 30
the range is the maximum divided by the minimum.
