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2 years ago

If a patient needs 30 days supply of tablet two tablets four times a day how many tablets with a patient need for discharge

Mathematics

1 answer:

marissa [1.9K]2 years ago

6 0

Answer:

Total number of tablets needs to discharge = 240 tables

Step-by-step explanation:

Given:

Number of days tablet need = 30 days

Number of times per days need = 4 times

Number of tablet per time = 2 tablet

Find:

Total number of tablets needs to discharge = ?

Computation:

⇒ Total number of tablets needs to discharge = Number of days tablet need × Number of times per days need × Number of tablet per time

⇒ Total number of tablets needs to discharge = 30 × 4 × 2

⇒ Total number of tablets needs to discharge = 240 tables

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Add and Subtract Rational Expressions with a Common Denominator

Sladkaya [172]

Answer:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}$

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}$

Operating on the numerators:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}$

Removing parentheses:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}$

Simplifying:

$\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}$

The expression cannot be further simplified.

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2 years ago

AE and DF are parallel. If √ABG = 11x and m_HCF = 10x + 9, what is m√ABG? 102° 99° 81° 9°

katrin [286]

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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zepelin [54]

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