Answer:
Step-by-step explanation:
Given two parametric equations
and
, the first derivative can be found using the following equation:
![\frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D%20%5Cfrac%7B%5Cfrac%7Bdy%7D%7Bdt%7D%7D%7B%5Cfrac%7Bdx%7D%7Bdt%7D%7D)
In this problem,
and
. Finding the derivative of each of these functions with respect to
gives us the following:
![\frac{dx}{dt} = 0](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%7D%7Bdt%7D%20%3D%200)
![\frac{dy}{dt} = 3^{3t + 1}\log{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%20%3D%203%5E%7B3t%20%2B%201%7D%5Clog%7B3%7D)
Because
, that means the function is a vertical line and has an infinite first derivative.
Answer:
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Answer:
Step-by-step explanation:
We are given the following in the question:
The needle size should not be too big and too small.
The diameter of the needle should be 1.65 mm.
We design the null and the alternate hypothesis
![H_{0}: \mu = 1.65\text{ mm}\\H_A: \mu \neq 1.65\text{ mm}](https://tex.z-dn.net/?f=H_%7B0%7D%3A%20%5Cmu%20%3D%201.65%5Ctext%7B%20mm%7D%5C%5CH_A%3A%20%5Cmu%20%5Cneq%201.65%5Ctext%7B%20mm%7D)
Sample size, n = 35
Sample mean,
= 1.64 mm
Sample standard deviation, s = 0.07 mm
Type I error:
- It is the error of rejecting the null hypothesis when it is true.
- It is also known as false positive error.
- It is the rejecting of a true null hypothesis.
Thus, type I error in this study would mean we reject the null hypothesis that the average diameter is 1.65 mm but actually the average diameters of the needle is 1.65 mm.
Thus, average diameter is 1.65 mm and we decide that it is not 1.65 mm.
Answer:
5b-5
Step-by-step explanation:
5(b - 1)
5(b) 5(-1)
5b-5