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2 years ago

Victor has saved $89.25 for the bicycle that he wants. The bicycle costs $129.85. Victor

Mathematics

1 answer:

serious [3.7K]2 years ago

5 0

Answer:

Victor's equation did not correctly model the problem.

The equation that correctly modeled the problem:

$129.85-$89.25=$40.60

Step-by-step explanation:

The amount required for bicycle purchase by Victor is $129.85 out of which $89.25 has been saved,in other words,the balance required for Victor to reach his target purchase price is the difference between the total cost of $129.85 and the $89.25 already saved.

The balance required=$129.85-$89.25=$40.6

This shows that the equation put forward by Victor is wrong.

An equation that correctly represents the problem is the difference between the target savings and the amount already saved as stated above

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one rectangle measures 2 units by 7 units. a second rectangle measures 11 units by 37 units. are these two figures scaled versio

Amanda [17]

Answer: The both triangle are not scale version to each other.

Explanation:

It is given that the one rectangle measures 2 units by 7 units. a second rectangle measures 11 units by 37 units.

The two shapes are scaled version of each other if their corresponding sides are in same proportion. In other words the if two shapes scaled version of each then the shapes are similar.

The sides or first rectangle are 2 and 7. The measures of second rectangle are 11 and 37.

The proportion of small side is,

$\frac{2}{11}$

The proportion of large side is,

$\frac{7}{37}$

So,

$\frac{2}{11}\neq \frac{7}{37}$

Since the proportion are not equal, therefore both triangle are not scale version to each other.

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3 years ago

Use the quadratic formula to solve x2 + 9x + 10 = 0.<br> What are the solutions to the equation?

vampirchik [111]

Answer:

$\large\boxed{x=\dfrac{-9\pm\sqrt{41}}{2}}$

Step-by-step explanation:

$\text{The quadratic formula of}$

$ax^2+bx+c=0$

$\text{If}\ b^2-4a0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\=========================================$

$\text{We have}\ x^2+9x+10=0\\\\a=1,\ b=9,\ c=10\\\\\text{substitute:}\\\\b^2-4ac=9^2-4(1)(10)=81-40=41>0\qquad _{\text{two solutions}}\\\\\sqrt{b^2-4ac}=\sqrt{41}\\\\x=\dfrac{-9\pm\sqrt{41}}{2(1)}=\dfrac{-9\pm\sqrt{41}}{2}$

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2 years ago

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2 years ago

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Snezhnost [94]

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Step-by-step explanation:

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