The half-life of the given exponential function is of 346.57 years.
<h3>What is the half-life of an exponential function?</h3>
It is the value of t when A(t) = 0.5A(0).
In this problem, the equation is:
.
In which t is measured in years.
Hence the half-life is found as follows:
![0.5A(0) = A(0)e^{-0.002t}](https://tex.z-dn.net/?f=0.5A%280%29%20%3D%20A%280%29e%5E%7B-0.002t%7D)
![e^{-0.002t} = 0.5](https://tex.z-dn.net/?f=e%5E%7B-0.002t%7D%20%3D%200.5)
![\ln{e^{-0.002t}} = \ln{0.5}](https://tex.z-dn.net/?f=%5Cln%7Be%5E%7B-0.002t%7D%7D%20%3D%20%5Cln%7B0.5%7D)
![0.002t = -\ln{0.5}](https://tex.z-dn.net/?f=0.002t%20%3D%20-%5Cln%7B0.5%7D)
![t = -\frac{\ln{0.5}}{0.002}](https://tex.z-dn.net/?f=t%20%3D%20-%5Cfrac%7B%5Cln%7B0.5%7D%7D%7B0.002%7D)
t = 346.57 years.
More can be learned about exponential functions at brainly.com/question/25537936
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3: (35,12000)
4: 10 and 60
5: around 7700?
Insert x = 7
so 3/(7+2) - sqr (7-3)
=3 / (9) - sqr (4)
= 1/3 - 2
=1/3 - 6/3
= -5/3
The answer to the question is (x+14)•(x+14)