PLEASE HELP, MARKING BRAINLIEST!!! What is the surface area of the cone ?

Identify any solutions to the system given below. 2x + y = 5 3y = 15 – 6x (6, –7) (2, 1) (–2, –9) (–4, 13)

sashaice [31]

Answer:

The answer (2, 1), (-4,13), (6,-7)

Step-by-step explanation:

Consider 2x+y=5 as equation 1, and 3y=15-6x as equation 2

1. Substituting values x and y with x=2 and y=1 as given by the coordinates (2,1)

Equation 1

2(2)+1=5 therefor it holds

Equation 2

3(1)=15-(6×2) also holds

2. Substituting values x and y with x=6 and y=-7 as given by the coordinates (6,-7)

Equation 1

2(6)+(-7)=5

5=5 holds

Equation 2

3(-7)=15-(6×6)

-21=-21 also holds

3. Substituting values x and y with x=-4 and y=13 as given by the coordinates (-4,13)

Equation 1

2(-4)+13=13-8=5 holds

Equation 2

3(13)=15-(6×-4)=39 also holds

4. Substituting values x and y with x=-2 and y=-9 as given by the coordinates (-2,-9)

Equation 1

2(-2)+(-9)=-4-9=-13≠5 does not hold

Equation 2

3(-9)≠15-(6×-2)

-27≠27 does not hold

The coordinates (2,1), (-4,13) and (6,-7) can be used as solutions to the system given

8 0

4 years ago

Read 2 more answers

50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the instanteous rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at exactly t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0

3 years ago

Math question down below

klio [65]

The dog with the weight of 110lbs is the outlier in the equation--since the other dogs only range from 20 to 35 lbs.

7 0

3 years ago

Read 2 more answers

Question 2.what is the probability that between 80 and 115 complaints are received in one week? use a n(110,20) model to approxi

AURORKA [14]

Calculate standard Z values for the given data:-

z = (80 - 110) / 20 = - 3/2 = -1.5

and z = (115 - 110) / 20 = 0.25

so we need Prob ( -1.5 < z < 0.25)

Using standard tables this comes to 0.5319 Answer

6 0

4 years ago

Write an expression for the product of z and 113, minus 300.

padilas [110]

Answer:

z*113 -300

Step-by-step explanation:

(z*113) -300

8 0

3 years ago