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2 years ago

What is the input value other than 7 for which g(x) = 4? X =

Mathematics

1 answer:

murzikaleks [220]2 years ago

6 0

Answer:

x = -8

Step-by-step explanation:

The input value other than 7 for which g( x ) = 4

x = -8

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The amount ofmoney is in the ratio 8:3 if the first amount is 9.92 what is the second amount?

BARSIC [14]

Answer:

The second amount is 3.72

Step-by-step explanation:

Given

$First : Second = 8 : 3$

$First = 9.92$

Required

Find Second

$First : Second = 8 : 3$

Substitute 9.92 for First

$9.92: Second = 8 : 3$

Express as fraction

$\frac{Second}{9.92} = \frac{3}{8}$

Multiply both sides by 9.92

$9.92 * \frac{Second}{9.92} = \frac{3}{8}*9.92$

$Second = \frac{3}{8}*9.92$

$Second = 3.72$

5 0

2 years ago

Please help me I can’t fail it

Hoochie [10]

Answer:

Step-by-step explanation:

1.rational

2.irrational

3.rational

4.rational

5.rational

6.irrational

8 0

2 years ago

The polynomial x^2+3x-1 is a factor of x^4+3x^3-2x^2-3x+1 true or false?

pashok25 [27]

Answer:

Yes, it is true that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ .

Step-by-step explanation:

Let us try to factorize $x^4+3x^3-2x^2-3x+1$

$x^4+3x^3-2x^2-3x+1\\\Rightarrow x^4-2x^2+1-3x+3x^3$

Let us try to make a whole square of the given terms:

$\Rightarrow (x^2)^2-2\times x^2 \times 1+1^2+3x^3-3x\\\Rightarrow (x^2-1)^2+3x^3-3x\\$

--------------

Formula used above:

$a^{2} -2 \times a \times b +b^{2} = (a-b)^2$

In the above equation, we had $a = x, b = 1$ .

--------------

Further solving the above equation, taking $3x$ common out of $3x^3-3x$

$\Rightarrow (x^2-1)^2+3x(x^2-1)\\$

Taking $(x^{2} -1)$ common out of the above term:

$\Rightarrow (x^2-1)((x^2-1)+3x)\\\Rightarrow (x^2-1)(x^2+3x-1)$

So, the two factors are $(x^2-1)\ and\ (x^2+3x-1)$ .

$\therefore$ The statement that $x^2+3x-1$ is a factor of $x^4+3x^3-2x^2-3x+1$ is True.

7 0

2 years ago

3^4 x 3^8= 3 to the power of what

Katen [24]

Answer:

3^12

Step-by-step explanation:

When the whole numbers are the same, add the exponents

6 0

2 years ago

AB is included between A. BC and AC B. C. < A and D. AB and BC

Novay_Z [31]

Answer:

Option C.

Step-by-step explanation:

By the property of unique triangles (ASA), one side is included between the two angles.

By this property, if included side of the triangle ABC is AB then this side will be included between the two angles A and B.

Therefore, $\bar{AB}$ is included between ∠A and ∠B.

Option C. will be the answer.

5 0

2 years ago