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Ymorist [56]
3 years ago
7

Help plz..will give the brainliest!!need step by step explanation .​

Mathematics
1 answer:
joja [24]3 years ago
6 0

Answer:

=8

Step-by-step explanation:

\log _2\left(16\right)\log _3\left(9\right)\\\mathrm{Simplify}\:\log _2\left(16\right):\quad 4\\\log _2\left(16\right)\\\mathrm{Rewrite\:}16\mathrm{\:in\:power-base\:form:}\quad 16=2^4\\=\log _2\left(2^4\right)\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)\\\log _2\left(2^4\right)=4\log _2\left(2\right)\\=4\log _2\left(2\right)\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(a\right)=1\\\log _2\left(2\right)=1\\=4\cdot \:1

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:1=4\\=4\\=4\log _3\left(9\right)\\\mathrm{Simplify}\:\log _3\left(9\right):\quad 2\\\log _3\left(9\right)\\\mathrm{Rewrite\:}9\mathrm{\:in\:power-base\:form:}\quad 9=3^2\\=\log _3\left(3^2\right)\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)\\\log _3\left(3^2\right)=2\log _3\left(3\right)\\=2\log _3\left(3\right)\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(a\right)=1\\\log _3\left(3\right)=1\\=2\cdot \:1

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:1=2\\=2\\=4\cdot \:2\\\mathrm{Multiply\:the\:numbers:}\:4\cdot \:2=8\\=8

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You have f(x)=(<span>6x+9)/(x-5) and want to find the inverse function?  Please note that the parentheses are obligatory here.

1.  Replace "f(x)" with y:   y = </span>(6x+9)/(x-5)
<span>
2.  Interchange the variables x and y:     x</span> = (6y+9)/(y-5)

3.  Solve this result for y:     x(y-5) = (6y+9), or xy-5x = 6y+9.  Then:
                                                             
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                     Then                      y = --------------                       
                                                             x-6

Here x may not = 6, because division by zero would occur otherwise.
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3 years ago
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