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3 years ago

Square A B C D is shown. Each side is 30 yards long. A diagonal is drawn from point D to point B to form 2 triangles.

Mathematics

2 answers:

navik [9.2K]3 years ago

6 0

Answer:

C. 30√2 yd

Step-by-step explanation:

Viktor [21]3 years ago

5 0

Answer:

Length = 30√2 yards.

Step-by-step explanation:

There is a plot of land of square shape that has 30 yards on each side. Jules owns this plot. He plans to divide the land in half by building a fence along the diagonal of the plot.

We have to calculate the length of the fence.

Now, the length of the diagonal will be the length of the fence.

So, the length = $\sqrt{30^{2} + 30^{2}} = 30\sqrt{2}$ yards. (Answer)

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Answer:

Let's see what to do buddy..

Step-by-step explanation:

_________________________________

STEP (1)

We know that the quadratic functions form are like this :

$y = a \: {x}^{2} + b \: x + c$

The quadratic function opens upward so ;

$a > 0$

The axis of parabolic symmetry passes through the vertex of the parabolic.

So we know that x vertex is equal to -2.

The vertex's x is finding from this equation:

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So we have :

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Multiply the sides of the equation by <em>2</em><em>a</em> :

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_________________________________

STEP (2)

A quota passes through points (-3,2) and (0,11) , so points (-3,2) and (0,11) must be true in the quota equation.

$y = f(x) = a{x}^{2} + bx + c \\ \\b = 4a \\ \\ y = f(x) = a {x}^{2} + 4ax + c$

$f( - 3) = 2 \\ \\ a ({ - 3})^{2} + 4a( - 3) + c = 2 \\ \\ 9a - 12a + c = 2 \\ \\ - 3a + c = 2 \\ \\ \\ \\ f(0) = 11 \\ \\ a ({0})^{2} + 4a(0) + c = 11 \\ \\ c = 11$

$- 3a + c = 2 \\ \\ c = 11 \\ \\ - 3a + 11 = 2 \\ 11 \: goes \: to \: the \: other \: side \: \\ \\ - 3a = 2 - 11 \\ - 3a = - 9 \\ divided \: the \: sides \: of \: the \: equation \: by \: - 3 \\ a = 3$

And we're done.

Thanks for watching buddy good luck.

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