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4 years ago

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Which is a quadratic function having a leading coefficient of 3 and a constant term of –12? f(x) = –12x2 + 3x + 1 f(x) = 3x2 + 1

1x – 12 f(x) = 12x2 + 3x + 3 f(x) = 3x – 12

2 answers:

Sever21 [200]4 years ago

8 0

A(x^2) + B (x) + C

Leading term: A
Constant term: C

f(x) = 3x^2 + 11x – 12

Lera25 [3.4K]4 years ago

4 0

I think it is f(x)= 3x2+11x-12

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