It is clear that a(n)=2^(1-2^(-n)). In fact, for n=1 this produces 2^(1-1/2)=sqrt(2)=a1 and if it is true for a(n) then a(n+1) = sqrt (2 * 2^(1-2^(-n))) = sqrt(2^(2-2^(-n))) = 2^(1-2^(-(n+1))) (a) clearly 2^(1-2^(-n))<2<3 so the sequence is bounded by 3. Also a(n+1)/a(n) = 2^(1-2^(-n-1) - 1+2^(-n)) = 2^(1/2^n - 1/2^(n+1)) = 2^(1/2^(n+1)) >1 so the sequence is monotonically increasing. As it is monotonically increasing and has an upper bound it means it has a limin when n-> oo (b) 1-1/2^n -> 1 as n->oo so 2^(1-2^(-n)) -> 2 as n->oo
Answer:
The correct answer is A)
Explanation:
In Act 3 Scene 1, the following enter the stage: Claudius, Gertrude, Polonius, Ophelia, Rosencrantz, and Guildenstern.
A conversation ensues about Hamlet as they try to determine the state of his emotions.
Between lines 30 and 38, Claudius to Gertrude states that they have arranged for Hamlet to run into Ophelia. Their plot is to establish for a fact that his recent mood swing and unsettling countenance and attitude is because of his feelings of love for Ophelia.
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The gerber baby is a baby, a logo
Answer:
that's are the tree reason of vietnam memorial controversial
Inscribed in the memorial are the names of service members classified as "declared dead"; as the memorial contains names of individuals who had died due to circumstances other than killed in action, including murder, vehicle accidents, drowning, heart attack, animal attack, snake bites and others. Also included are the names of those whose status is unknown, which typically means "missing in action" (MIA). The names are inscribed in Optima typeface, designed by Hermann Zapf. Information about the rank, unit, and decorations are not given.
