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Oduvanchick [21]
3 years ago
9

I EILL MAKE BRAINLEST NEED HELP ASAP MT TEACHER IS ABOUT TO YELL WT ME PLEASE PLEASE PLEASE PLEASE PLEASE

Mathematics
1 answer:
Korvikt [17]3 years ago
8 0
Ok, what class is this
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When deriving the quadratic formula by completing the square, what expression can be added to both sides of the
liubo4ka [24]

Answer:

The element you add is      b^2 / 4a

Step-by-step explanation:

The element you add is      b^2 / 4a

Remember that

a x^2 + bx +c  \\= a ( x^2 +(b/a)x ) + c

So, in order to complete the square you add   (b/2a)^2

But when you multiply times  a   you get

b^2 / 4a

7 0
3 years ago
Read 2 more answers
Is AP Calculus more difficult than AP Statistics?
Natali5045456 [20]

Answer:

no both are "=" hard

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If f(–5) = 0, what are all the factors of the function f (x ) = x cubed minus 19 x + 30? Use the Remainder Theorem.
oksian1 [2.3K]
(x + 5) (x - 2) (x - 3)

4 0
3 years ago
P, Q, and R are three different points. PQ = 3x + 2, QR = x, RP = x + 2, and . List the angles of PQR in order from largest to
horsena [70]
<span>PQR is a triangle
QR = x  </span>⇒ x>0
If x>0 then:
QR is the smallest side
PQ is the largest side

<span>In the triangle, the largest angle lies opposite the largest side.
</span>The angles of Δ<span>PQR in order from largest to smallest:
</span>∠R is largest    [opposite to PQ]
∠Q is middle    [opposite to RP]
∠P is smallest   [opposite to QR] 
4 0
3 years ago
A ball is projected in to the air. Its height at time t is given by the equation
Ksju [112]
The equation gives the height of the ball. That is, h is the height of the ball. t is the time. Since we are looking for the time at which the height is 8 (h=8), we need to set the equation equal to 8 and solve for t. We do this as follows:

h=-16 t^{2} +60t+1
8=-16 t^{2} +60t+1
16 t^{2} -60t-1+8=0
16 t^{2} -60t+7=0

This is a quadratic equation and as it is set equal to 0 we can solve it using the quadratic formula. That formula is:
t= \frac{-bplus minus \sqrt{ b^{2}-4ac } }{2a}
You might recall seeing this as "x=..." but since our equation is in terms of t we use "t-=..."

In order to use the formula we need to identify a, b and c.
a = the coefficient (number in front of) t^{2} = 16.
b = the coefficient of t = -60
c = the constant (the number that is by itself) = 7

Substituting these into the quadratic formula gives us:
t= \frac{-(-60)plus minus \sqrt{ (-60)^{2}-4(16)(7) } }{2(16)}
t= \frac{60plus minus \sqrt{3600-448 } }{32}
t= \frac{60plus minus \sqrt{3152 } }{32}

As we have "plus minus" (this is usually written in symbols with a plus sign over a minus sign) we split the equation in two and obtain:
t=  \frac{60+56.1426}{32} =3.63
and
t=  \frac{60-56.1426}{32} =.12

So the height is 8 feet at t = 3.63 and t=.12

It should make sense that there are two times. The ball goes up, reaches it's highest height and then comes back down. As such the height will be 8 at some point on the way up and also at some point on the way down.


3 0
3 years ago
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