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nika2105 [10]
3 years ago
11

How much longer is a 1-inch button than a 3/8-inch button?

Mathematics
1 answer:
Daniel [21]3 years ago
6 0

Answer:

5/8

Step-by-step explanation:

If you take 1/1 and subtract it by 3/8 you will get the answer 5/8

So the 1 inch button is 5/8 longer than the 3/8 button.

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Factor and solve the following equation 2x^2 + x - 21 = 0.
umka21 [38]

Answer:

x = -7/2 and 3

Step-by-step explanation:

Use foil. Solve for x.

8 0
3 years ago
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HELP PLS ‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎ ‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎
VikaD [51]

Answer:

with what 0-0 are youy okay?

Step-by-step explanation:

8 0
3 years ago
What does 3 - 11 - (-6) equal?
djyliett [7]

Answer:

-2

Step-by-step explanation:

3-11+6

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4 0
3 years ago
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Pizza Paradise offers 4 types of crust, 10 toppings, and 8 kinds of cheese for the mega calzone. How many different mega calzone
Bumek [7]

Answer:

26880 ways

<em></em>

Step-by-step explanation:

Given

Crust = 4

Toppings = 10

Cheese = 8

Required

Determine the number of ways 3 toppings and 3 cheese can be selected

The number of crusts to be selected was not stated. So, I'll assume 1 crust to be selected from 4.

This can be done in ^4C_1 ways

For the toppings:

3 can be selected from 10 in ^{10}C_3 ways

For the cheeses:

3 can be selected from 8 in ^{8}C_3 ways

Total number of selection is:

Total = ^4C_1 * ^{10}C_3 * ^{8}C_3

Apply combination formula:

Total = \frac{4!}{(4-1)!1!} * \frac{10!}{(10-3)!3!} * \frac{8!}{(8-3)!3!}

Total = \frac{4!}{3!1!} * \frac{10!}{7!3!} * \frac{8!}{5!3!}

Total = \frac{4*3!}{3!*1} * \frac{10*9*8*7!}{7!*3*2*1} * \frac{8*7*6*5!}{5!*3*2*1}

Total = \frac{4}{1} * \frac{10*9*8}{3*2*1} * \frac{8*7*6}{3*2*1}

Total = 4 * \frac{720}{6} * \frac{336}{6}

Total = 4 * 120* 56

Total = 26880

<em>Hence, there are 26880 ways</em>

5 0
3 years ago
Please explain how to do #6 i know the work is right but i don’t understand it
mariarad [96]
Since this is part of a packet, there's a lot of prior knowledge you need to understand the question.
1) The angle of elevation is the angle between the horizontal and the light of sight from the object to the observer (see picture 1).

2) A lot of the units are from work done by an Indian astronomer. The line of sight (light blue in picture 1) is r = 3438 (I think you might have forgotten to finish writing the number). r, or 3438, is the distance from the earth to the sun used by Indian Astronomers. 

3) The table shows units in jya(θ<span>°). Jya is a Sanskrit (ancient Indian language) word. It stands for the length of half of a chord that connects two endpoints of a circle (kinda confusing and more information than you need to know - but it's the green line in picture 2).
What's important is: </span>jya(θ°) = r*sin(θ°)



Now let's tackle the problem:
1) You know that the angle of elevation is 67.5°. Using the chart, the only important value is the second from the bottom. jya(67.5°) = 3177. 

2) Remember that jya(θ°) = r*sin(θ°). 
Also remember that sine of an angle is \frac{opposite}{hypotenuse}. In this problem, r, the distance from the earth to the sun, happens to be the hypotenuse of the triangle since its the longest edge. 

3) Notice that you're dividing jya(θ°) (aka r*sin(θ°)) by r = 3438. That will give you sin(θ°) by itself. Then you're multiplying that sin(θ°) by 1 AU, which we are told is the actual distance of the hypotenuse/distance from earth to sun. Since sine = \frac{opposite}{hypotenuse} that gives you the apparent length of the opposite side = apparent height of the sun.

The math is a bit weird, but you're basically multiplying sine by the apparent distance 1AU to get the apparent height, instead of multiplying sine by the estimated height r = 3438. Dividing 3177 by 3438 gives you sin(67.5°). Then multiplying sin(67.5°) by the apparent hypotenuse, 1AU, gives you the apparent height. That's how I'm understanding it!

6 0
3 years ago
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