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3 years ago

What does 3 - 11 - (-6) equal?

Mathematics

2 answers:

77julia77 [94]3 years ago

6 0

Answer:

-2

Step-by-step explanation:

Multiply

− 1 by − 6 . 3

− 11 + 6 Subtract 11 from 3

. − 8 + 6

Add − 8 and 6 . − 2

djyliett [7]3 years ago

4 0

Answer:

-2

Step-by-step explanation:

3-11+6

-8+6

-2

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The chance to land on the number three is only a ¼ or 0.25 chance. Knowing that we can also understand the law of large numbers. The law of large numbers states that as the number of spins gets very large, eventually the experimental probability will reach the theoretical probability. Eight spins of the spinner is not a large number, so the probabilities will be different. In this case resulting in zero times landing on three. Therefore, Megan should not be concerned that the spinner is unfair.

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3 years ago

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Help me with #22 Please i need steps too

VladimirAG [237]

Answer:

$\frac{1}{2} (8)(x+4)=3(x+6)\\x=2$

Step-by-step explanation:

$\frac{1}{2} bh=bh\\\\\frac{1}{2}(8)(x+4)=3(x+6)\\4(x+4)=3x+18\\4x+16=3x+18\\4x=3x+2\\x=2$

1. set the equation for the area of each shape equal to each other

2. simplify each side until you get $4x+16=3x+18$

3. subtract 16 from both sides which will give you $4x=3x+2$

4. subtract 3x from both sides which will give you the value of x. $x=2$

5. check that $x=2$ is correct by plugging it into the equations

triangle:

$area=\frac{1}{2} (8)(2+4)\\area=4(6)\\area=24$

rectangle:

$area=3(2+6)\\area=3(8)\\area=24$

the areas are the same

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3 years ago

9. Three dice are tossed. Find the probability of the specified event.<br> A sum of 5

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A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d

bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

Sample size n > 30
Sample mean = $\overline{x}$
Sample standard deviation = s
Population standard deviation = $\sigma$
Level of significance = $\alpha$

Then the confidence interval is obtained as

Case 1: Population standard deviation is known

$\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}$

Case 2: Population standard deviation is unknown.

$\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}$

For this case, we're given that:

Sample size n = 90 > 30
Sample mean = $\overline{x}$ = 138
Sample standard deviation = s = 34
Level of significance = $\alpha$ = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: $Z_{0.1/2}$ = ±1.645

Thus, we get:

$CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]$

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

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At a raffle, 250 tickets are sold at $1 each for 3 prizes of $100, $50, and $10. You buy 1 ticket. What is the expected value of

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Answer

1: 60

2: 150

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