IQR = 40
1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.
We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.
40, 45, 50, 60, 60, 75, 90, 90, 120
Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;
IQR = 90 - 50 = 40
Answer:
(a) 1km
(b)80 fence panels
Step-by-step explanation:
(a) perimeter = 300+300= 600
200+200= + 400
=1000m
1km = 1000m
(b).
1panel = 2.5 m 1× 200÷2.5 = 80
=200m
Answer:
x = -8
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
4(3x−2)=8(2x+3)
(4)(3x)+(4)(−2)=(8)(2x)+(8)(3)(Distribute)
12x+−8=16x+24
12x−8=16x+24
Step 2: Subtract 16x from both sides.
12x−8−16x=16x+24−16x
−4x−8=24
Step 3: Add 8 to both sides.
−4x−8+8=24+8
−4x=32
Step 4: Divide both sides by -4.
−4x
−4
=
32
−4
x=−8
Answer:
x=−8
the equation of a vertically opening parabola is
(x - h)² = 4p(y - k)
where (h, k) are the coordinates of the vertex and p is the distance of the focus and directrix from the vertex. If 4p is positive parabola opens up and if 4p is negative parabola opens down
rearrange 12y = (x - 1)² - 48 into this form
(x - 1)² = 12y + 48
(x - 1)² = 12( y + 4) ← in standard form
Vertex = (1, - 4 )
4p = 12 ⇒ p = 3 ⇒ parabola opens upwards
the focus is above the vertex and the directrix is below the vertex in a vertically opening up parabola
Focus = (1, - 4 + 3 ) = (1, - 1)
Directrix has equation y = - 4 - 3 ⇒ y = - 7
