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Alja [10]
3 years ago
13

What's The Domain And Range

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
6 0
The domains are the first ones like 5,2,-3,-1, 7 and range are the second ones
You might be interested in
The integer whose product with (-1) is 22 is​
nadya68 [22]

Answer:

-22

Step-by-step explanation:

According to the question you need to find a number that gives the result of 22 when multiplied with -1

So, -22 X (-1) = +22

6 0
3 years ago
Raju bought an old car for Rs.125000 and spent Rs.25000 on its repair . He sold the car for Rs.200000 . Find his gain or loss pe
Keith_Richards [23]

Answer: 33.33\%

Step-by-step explanation:

Given

Raju buy an old car for Rs\ 1,25,000

He spent Rs\ 25000 on its repair

The selling price of the car  Rs\ 2,00,000

So, the cost price is

\Rightarrow C.P.=1,25,000+25,000=Rs\ 1,50,000

Here, S.P.> C.P.\quad \text{i.e. gain}

Gain percent is

\Rightarrow \text{Gain percent}=\dfrac{2,00,000-1,50,000}{1,50,000}\times 100=\dfrac{50,000}{1,50,000}\times 100\\\Rightarrow \text{Gain percent}=33.33\ \%

6 0
3 years ago
I need help can anyone help me please??
Lisa [10]

what do u need help w lol

8 0
2 years ago
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair a
vesna_86 [32]
Chair=x

Table=y

Desk=z

\begin{Bmatrix}x+y&=&40\\y+z&=&83\\x+z&=&77\end{matrix}

keep the first row as normal, then in the other ones, we can isolate Y and X

\begin{Bmatrix}x+y&=&40\\y&=&83-z\\x&=&77-z\end{matrix}

now we can replace at first row...

\begin{Bmatrix}(77-z)+(83-z)&=&40\\y&=&83-z\\x&=&77-z\end{matrix}

\begin{Bmatrix}160-2z&=&40\\y&=&83-z\\x&=&77-z\end{matrix}

\begin{Bmatrix}-2z&=&40-160\\y&=&83-z\\x&=&77-z\end{matrix}

\begin{Bmatrix}-2z&=&-120\\y&=&83-z\\x&=&77-z\end{matrix}

\begin{Bmatrix}z&=&60\\y&=&83-z\\x&=&77-z\end{matrix}

now we can replace the Z to discovery the other value

\begin{Bmatrix}z&=&60\\y&=&83-60\\x&=&77-60\end{matrix}

\boxed{\boxed{\boxed{\begin{Bmatrix}Chair&=&17\\Table&=&23\\Desk&=&60\end{matrix}}}}
6 0
3 years ago
(If I think it’s right I’ll make you brainless answer) Mark is building a scale model of his car as shown in the diagram. The ac
sasho [114]
The first part cannot be answered here without the diagram. However, I can tell you that the model he's building is 1/10 the size of the actual car. That means every measurement on the car is divided by 10 to get the model measurement.

The radius of the car wheel is 27 inches, so the diameter is 54 inches. Using what we know about the model, the correct proportions for the model wheel diameters would be 54 / 10, or 5.4, inches. Therefore, wheels with a diameter of 6 inches would not be in proportion with the model.
8 0
3 years ago
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