The smallest (whole number ) 6 digit number is 1,000,000
The greatest (whole number 4 digit number is 9,999
The difference between them means to subtract the four digit number from the 6 digit number.
The difference is 990,001
I would not consider 000001 to be a 6 digit number (in case this is supposed to be a trick question.)
The general equation of a hyperbola with a horizontal transverse axis is defined as:
x²/a² - y²/b² = 1
Solving for b², we use the formula: a² + b² = c²
b² = 12² - 9² = 63
Equation of our hyperbola will be:
x²/81 - y²/63 = 1
If scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points, then the minimum score you would need to be in the top 2% is equal to 88.929.
A problem of this type in mathematics can be characterized as a normal distribution problem. We can use the z-score to solve it by using the formula;
Z = x - μ / σ
In this formula the standard score is represented by Z, the observed value is represented by x, the mean is represented by μ, and the standard deviation is represented by σ.
The p-value can be used to determine the z-score with the help of a standard table.
As we have to find the minimum score to be in the top 2%, p-value = 0.02
The z-score that is found to correspond with this p-value of 0.02 in the standard table is 2.054
Therefore,
2.054 = x - 76.4 ÷ 6.1
2.054 × 6.1 = x - 76.4
12.529 = x - 76.4
12.529 + 76.4 = x
x = 88.929
Hence 88.929 is calculated to be the lowest score required to be in the top 2%.
To learn more about normal distribution, click here:
brainly.com/question/4079902
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