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Temka [501]
3 years ago
11

Write an equation to represent the problem. Two years of local internet service costs $685 including the installation fee of $85

. What is the monthly fee?
Mathematics
1 answer:
BaLLatris [955]3 years ago
3 0
You do 685 minus the 85 and then the 600 divided by 24
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2 years ago
Which pair of words describes this system of equations 3y=9x-6 2y+6x=4
pishuonlain [190]

Answer:

Consistent and dependent

Step-by-step explanation:

Given

3y = 9x - 6

2y + 6x = 4

Required

The words that describe the equations

Make y the subject in (2)

2y + 6x = 4

Collect like terms

2y = 4 - 6x

Divide through by 2

y = 2 - 3x

Substitute: y = 2 - 3x in (1)

3y = 9x - 6

3(2 - 3x) = 9x - 6

6 - 9x = 9x - 6

Collect like terms

9x+9x = 6+6

18x = 12

Solve for x

x = \frac{12}{18}

Simplify

x = \frac{2}{3}

Substitute x = \frac{2}{3} in y = 2 - 3x

y = 2 - 3*\frac{2}{3}

y = 2 - 2

y =0

So, we have:

x = \frac{2}{3} and y =0

<em>The system is consistent because it has at least 1 solution</em>

<em>The system is dependent because it has more than 1 solution</em>

6 0
3 years ago
Bus A and Bus B leave the bus depot at 8 am.
LenaWriter [7]

Answer: 10:55

Step-by-step explanation:

Taking statement at face value and the simplest scenario that commencing from 08:00am the buses take a route from depot that returns bus A to depot at 25min intervals while Bus B returns at 35min intervals.

The time the buses will be back at the depot simultaneously will be when:

N(a) * 25mins = N(b) * 35mins

Therefore, when N(b) * 35 is divisible by 25 where N(a) and N(b) are integers.

Multiples of 25 (Bus A) = 25, 50, 75, 100, 125, 150, 175, 200 etc

Multiples of 35 (Bus B) = 35, 70, 105, 140, 175, 210, 245 etc

This shows that after 7 circuits by BUS A and 5 circuits by Bus B, there will be an equal number which is 175 minutes.

So both buses are next at Depot together after 175minutes (2hr 55min) on the clock that is

at 08:00 + 2:55 = 10:55

6 0
3 years ago
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