The approximate number of pink chips is 40. Here's why: what you need to do is set up the problem as shown below. 12 goes above 30 because you have to know what the total number of chips chosen is in order to relate it to 100 chips. From there, all you have to do is cross-multiply and divide (or my middle school teacher used to call it fish.... I'll explain why). First you are going to draw a line from the 100 to the 12 and multiply them. then you are going to curve the line that you will draw from the 12 to the 30 and divide the product of 12 and 100 by 30. Then you will draw a line from the 30 to the X meaning that the quotient that you find from the product of 120 and 100 divided by 30 equals X. Hope that helps.
12 x
30 100
Answer:
7/2 miles or 3 2/4 miles
Step-by-step explanation:
Answer:
336
Step-by-step explanation:
Required Formulas:-
1. Number of ways to select x things out of n things = ⁿCₓ
2. Number of ways to arrange n things when a things and b things are similar = n!/(a!*b!)
Since we have to choose 8 colors and we are having 3 different colors, it is only possible when we select 2 different colors (e.g. 5 red and 3 blue). To find all possible ways we will have to find all unique arrangements of selected color.
Using formula (1), number of ways to select 2 colors out of given 3 colors = ³C₂ = 3
Using formula (2), finding all unique arrangements when 5 stripes are of one color and 3 stripes are of second color = 8!/(3!*5!) = 56
Suppose, we can choose 5 stripes from red color and 3 stripes from blue color or 5 strips from blue color and 3 strips from red color. So there are 2 possibilities of arranging every 2 colors we choose .
∴ Answer=3*56*2 = 336
A) The empirical rule tells you the probability of being within 1 standard deviation of the mean is 68%.
b) The probability that the sample mean falls within 3 standard deviations* of the mean is 99.7%.
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* The standard deviation of the sample mean is 1/√9 = 1/3 of the standard deviation of an individual sample. Hence the same limits (90-110) now cover 3 standard deviations of the sample mean.
