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Sloan [31]
3 years ago
7

I need help with this question

Mathematics
1 answer:
AVprozaik [17]3 years ago
5 0

Step-by-step explanation:

Angle formed at the circumference of the circle is half of the angle formed at the center of the same circle.

Hence,

m\angle ADC =  \frac{1}{2} \times  m\angle ABC \\  \\  \therefore \: m\angle ADC =  \frac{1}{2} \times  40 \degree \\  \\ \therefore \:m\angle ADC =  20 \degree  \\  \\

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Please help!!!
Alex Ar [27]

Answer:

Check bolded below

Step-by-step explanation:

1)radius = 10 in (given), diameter = 2*radius = 2(10 in) = 20 in

formula for circumference => 2πr => 2π(10)

circumference = 20π in

2)diameter = 12 ft (given), radius = 1/2*diameter = 1/2(12 ft) = 6 ft

formula for circumference => 2πr => 2π(6)

circumference = 12π ft

3)radius = 3 m (given), diameter = 2*radius = 2(3 m) = 6 m

formula for circumference => 2πr => 2π(3)

circumference = 6π m

4)diameter = 18 cm (given), radius = 1/2*diameter = 1/2(18 cm) = 9 cm

formula for circumference => 2πr => 2π(9)

circumference = 18π cm

6 0
3 years ago
Read 2 more answers
What is the solution set of the equation 6/m +2= m+3/m−1 ?
laiz [17]

Answer:

m = (-3, 2) x = (-1)

Step-by-step explanation:

Just took this K12 test.

5 0
3 years ago
Which is equivalent to 34?
romanna [79]

Answer:

20+14

Step-by-step explanation:

Math

4 0
2 years ago
Write a situation that could be represented by the equation y=15x-3
Solnce55 [7]
A tree grows at a rate of 15 inches per year.  However, three inches were chewed off by quasi-sadistic bunnies the first year it was planted.  Fortunately, the bunnies were frightened off by the garden gnomes, and did not return.  As a result the tree was able to grow unencumbered for the rest of its life.
8 0
3 years ago
The equation of a parabola is given.y=1/8x^2+4x+20 What are the coordinates of the focus of the parabola?
Lena [83]
He equation of a parabola is x = -4(y-1)^2. What is the equation of the directrix? 
<span>You may write the equation as </span>
<span>(y-1)^2 = (1) (x+4) </span>
<span>(y-k)^2 = 4p(x-h), where (h,k) is the vertex </span>
<span>4p=1 </span>
<span>p=1/4 </span>
<span>k=1 </span>
<span>h=-4 </span>

<span>The directrix is a vertical line x= h-p </span>
<span>x = -4-1/4 </span>
<span>x=-17/4 </span>

<span>------------------------------- </span>
<span>What is the focal length of the parabola with equation y - 4 = 1/8x^2 </span>
<span>(x-0)^2 = 8(y-4) </span>
<span>The vertex is (0,4) </span>
<span>4p=8 </span>
<span>p=2 (focal length) -- distance between vertex and the focus </span>
<span>------------------------------- </span>
<span>(y-0)^2 = (4/3) (x-7) </span>
<span>vertex = (7,0) </span>
<span>4p=4/3 </span>
<span>p=1/3 </span>
<span>focus : (h+p,k) </span>
<span>(7+1/3, 0)</span>
8 0
3 years ago
Read 2 more answers
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