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Sloan [31]
3 years ago
7

I need help with this question

Mathematics
1 answer:
AVprozaik [17]3 years ago
5 0

Step-by-step explanation:

Angle formed at the circumference of the circle is half of the angle formed at the center of the same circle.

Hence,

m\angle ADC =  \frac{1}{2} \times  m\angle ABC \\  \\  \therefore \: m\angle ADC =  \frac{1}{2} \times  40 \degree \\  \\ \therefore \:m\angle ADC =  20 \degree  \\  \\

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If QS bisects PQT, SQT=(8x-25), PQT=(9x+34), and SQR = 112, find each measure
inna [77]

The value of

  • x = 12°
  • m∠PQS = 71°
  • m∠PQT = 142°
  • m∠TQR = 41°

Given

SQT = (8x₋25) and PQT = (9x₊34)

SQR = 112°

we need to find the x angle and the remaining angles.

we know that QS bisects ∠PQT

⇒ 2(8x₋25)° = (9x₊34)°

(16x ₋ 30)° =  (9x₊34)°

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x = 12°

substitute x value in the given values of angles.

m∠PQS = (8x ₋ 25)° = (8(12)₋25) = 71°

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Learn more about Angles here:

brainly.com/question/24839702

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