6>3/4... a number greater than one can be expressed as a fraction with a numerator greater than the denominator. Hope this helps...
Answer:
Answer: The statements are numbers 1, 3, 4
The non statements are 2, 5, 6
Step-by-step explanation:
Answer and Explanation:
Solution: The operation of concatenation for a set of string on p. and the set is
AB = {XY | X ∈ A and y ∈ B}.
We need to satisfy all these following properties to find out the standard set is closed under concatenation.
1- Union of two standard sets also belongs to the classic collection. For example, A and B are regular. AUB also belongs to a regular group.
2- Compliment of two standards set A and B are A’ and B’ also belonging to the standard set.
3- Intersection of two standards set A and B is A∩B is also a regular set member.
4- The difference between two regular sets is also standard. For example, the difference between A and B is A-B is also a standard set.
The closure of the regular set is also standard, and the concatenation of traditional sets is regular.
Answer:
No this is not a function.
Step-by-step explanation:
This is not a function because some of the x-values repeat, which is not how a function works. For this to be a function, each x-value would have to be different. In this case, the 4 and 5 repeat in the x-values.
If this answer is correct, please make me Brainliest!
Answer:
8) answer=5 9)answer=15
Step-by-step explanation:
all you have to do is replace in the following formula
Where
X1: is the first number of the first point
Y1: is the second number of the first point
X2: is the first number of the second point
Y2: is the second number of the second point
you replace in the formula and solve
I attach solution
