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Likurg_2 [28]
3 years ago
12

A rectangular pool is 20 feet wide and 50 feet long. A deck used for sunning surrounds the pool. The deck is the same width all

the way around the pool. The total area of the deck is 456 square feet. How wide is the deck around the pool?
Mathematics
1 answer:
rodikova [14]3 years ago
4 0

Answer:

  3 feet

Step-by-step explanation:

Let x represent the width of the deck. The deck adds to the pool dimensions on both sides, so the area of the site including pool and deck will be ...

  A = (20 +2x)(50 +2x) = 1000 +140x +4x^2

The area of the pool alone is

  A = (20)(50) = 1000

So, the area of the deck is the difference:

  456 = (4x^2 +140x +1000) -(1000)

Dividing by 4 and subtracting 114, we have ...

  x^2 +35x -114 = 0

  (x -3)(x +38) = 0

Solutions to this are x = 3 and x = -38. The positive solution is the one of interest.

The deck is 3 feet wide.

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The linear equation representing the above said pair of points is "y=12x+9"

Step-by-step explanation:

The given set of points are  

x Y

1 21

2 33

3 45

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For finding the linear equation for the given sets of value

We must know the generic form of a linear equation is y=m*x + c

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Thus slope ”m” = 33-21/2-1 = 12

we put slope “m” in the equation which becomes y=12x+c

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Answer:

The slope is \frac{3}{2}

The y-intercept is 9

Step-by-step explanation:

The form of the equation that passes through two points (x1, y1) and (x2, y2) is y = m x + b, where

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→ Subtract 3 from both sides

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