We can apply some rules backwards
first
f'(x)=
(x-4)(-2x+4)
-2x^2+12x-16
we know that
so therefor maybe
-2x^2=rnx^{n-1}
2=n-1
n=3
rn=-2
3r=-2
r=-2/3
one is
second part
12x
12x=
x^1, 1=n-1
n=2
rn=12
2r=12
r=6
is the second bit
last part
-16
-16x^0=
0=n-1
n=1
rn=-16
1r=-16
r=-16
-16x^1
so therfor f(x)=
D.8
A and C are out because they would get you ether lower or equal to 20, which is equal to AC and your trying to find X in AB which is so posed to be the what equals AC+BC.
AB=AC+BC
5x=20+BC
5(8)=20+BC
40=20+BC
40=20+20
AC equals 20. AB will have to equal AC+ CB. If you put in A.4 in AB 5X you will get twenty and that not what you want. You want to get a number that will get you the an answer greater to AC. So 5(8)=40.
Answer:
Tenths is the correct answer because the first digit after the decimal represents the tenths place. the next digit after the decimal represents the hundredths place the remaining digits continue to fill in the place values until there are no digits left.
Answer:
The range of the graph is [-10, 10]
Step-by-step explanation:
This represents how the y-values of the graph range from -10 to 10.
Because there are no arrow marks on the ends of the graph, we know that the graph stops there at -10 and 10 and doesn't go beyond that.
