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3 years ago

after 8% discount from the list price, the sale price price of a poster was $17.48. what was the list price of poster.

1 answer:

6 0

Well the answer would be $18.8784 but if you want it to be shorter it would be $18.88 because you multiply 17.48 and 0.08 and get 1.3984 and then you add it to $17.48

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HELP PLEASE! I would really appreciate it :)

dem82 [27]

Each time x increases by 2 (eg: from x = -3 to x = -1), the value of y increases by 7 (eg: y = 9.5 to y = 16.5)

Change in y = 7
change in x = 2
Slope = (change in y)/(change in x) = 7/2 = 3.5

This all means that we have a linear equation

4 0

3 years ago

Surface area of a prism please help its my last day 120 points

elena-s [515]

Answer:

Area of the base = (8×6)/2 = 24 yd²

Height of the prism = 8 yd

Perimeter of the base = 8+6+10 = 24 yd

Surface area = 2B + Ph = (2×24)+(24×8) = 48+192 = 240 yd²

5 0

3 years ago

Given the formula A = P(1 + )". compute A (rounded to two decimal places) if P = 10,000,7

Flura [38]

Answer:

A = 16010.32

Step-by-step explanation:

Given that,

$A=P(1+\dfrac{r}{k})^n$

Put P = 10,000, r = 0.08, k = 2 and n = 12 in the above formula to find A.

$A=10,000(1+\dfrac{0.08}{2})^{12}\\\\=10,000\times (1.04)^{12}\\\\=16,010.32$

So, the value of A is 16010.32. Hence, the correct option is (B).

4 0

2 years ago

Marie is purchasing a $108,000 home with a 30 year ortgage at 5.25%. What is her monthly principal and interest payment

schepotkina [342]

Answer:

Monthly interest rate is r=0,004375

Monthly principal c=590,625

Step-by-step explanation:

Monthly interest payment rate :

$r=\frac{5.25}{12}:100=0,0004375$

Now, we need to find monthly principal payment : $c=\frac{rP}{1-(1+r)^{-N}}$

Use this rule : $N=30*12=360$

P=108000

r=0,004375

$c=\frac{0.004375*108000}{1-(1+0.004375)^{-360}} =\frac{472.5}{0.8}=590,625$

5 0

3 years ago

Read 2 more answers

Look at the system of equations below.

Annette [7]

Answer:

Substitution and graphing are less efficient methods than elimination for this system as there is extra amount of steps we have to take to solve the same system of equations - hence time consuming and a margin or error may happen. Therefore, elimination is the suitable method for solving this system.

Step-by-step explanation:

Let us consider the system of equation below.

$4x-5y=3$

$3x+5y=13$

Elimination method sounds the most appropriate option to solve the given system of equations as we can easily sort out an equation in one variable x in minimal steps by just adding the both equations as the y-coefficient in the first equation is the opposite of the y-coefficient in the second equation, and we can determine an equation in one variable x.

Adding both equations will eliminate the y-variable and we can easily sort out the value of x from the resulting equation.

As the given system of equation

$4x-5y=3$ $......[1]$

$3x+5y=13$ $......[2]$

Adding Equation 1 and Equation 2

$4x-5y+3x+5y=3+13$

$7x=16$

$x=$ $\frac{16}{7}$

Putting $x=$ $\frac{16}{7}$ in Equation [1]

$4x-5y=3$ $......[1]$

$y=$ $\frac{43}{35}$

Although substitution or graphing methods can also be used to bring the solution of the given system of equations, but using substitution or graphing method can be sometimes cumbersome or time-consuming as it would have to take some additional steps to solve the system.

For example, if we would have to use the substitution methods to solve the given system of equations, first we would have to solve one of the equations by choosing one of the equation for one of the chosen variables and then putting this back into the other equation, and solve for the other, and then back-solving for the first variable.

As the given system of equation

$4x-5y=3$ $......[1]$

$3x+5y=13$ $......[2]$

Solving the equation 2 for x variable

$3x=13-5y$

$x=\frac{13-5y}{3}$

Plugging $x=\frac{13-5y}{3}$ in equation [1]

$4(\frac{13-5y}{3}) -5y=3$

$y = \frac{43}{35}$

Putting $y = \frac{43}{35}$ in Equation 2

$3x+5y=13$ $......[2]$

$x = \frac{16}{7}$

So, you can figure out, we have to make additional steps when we use substitution method to solve this system of equations.

Similarly, using graphing method, it would take a certain time before we identify the solution of the system.

Hence, from all the discussion and analysis we did, we can safely say that substitution and graphing are less efficient methods than elimination for this system as there is extra amount of steps we have to take to solve the same system of equations - hence time consuming and a margin or error may happen.

Therefore, we agree with the student argument that Elimination is the best method for solving this system because the y-coefficient in the first equation is the opposite of the y-coefficient in the second equation.

Keywords: substitution method, system of equations, elimination method

Lear more about elimination method of solving the system of equation from brainly.com/question/12938655

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4 0

3 years ago