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igomit [66]
3 years ago
9

What do the y intercept and the slope mean in the context of the example problem y=-4x+20

Mathematics
1 answer:
PtichkaEL [24]3 years ago
3 0

Answer:

Therefore,

Slope = -4\\\\y-intercept=20

Step-by-step explanation:

Intercepts:

The line which intersect on x-axis and y-axis are called intercepts.

There are two intercepts:

x-intercept: The line which intersect at x-axis. So when the line intersect at x-axis Y coordinate is zero.

y-intercept: The line which intersect at y-axis. So when the line intersect at y-axis X coordinate is zero.

Given:

y=-4x+20

We have General Equation for POINT-SLOPE form for a line is given as

y=mx+c

where,

m = Slope of Line

c = y-intercept

On Comparing the given Equation with Point-Slope form we have

m = Slope = -4\\\\c=20

Therefore,

Slope = -4\\\\y-intercept=20

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Step-by-step explanation:

<h3>It's False</h3>

Because (-5+ 1, - 2 + 6) = (- 4, 4) which is not equal to (-4, - 4).

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Josie bought a new mirror. The mirror has 5 sides. What is the shape of the mirror?
yuradex [85]
If Josie bought a mirror with 5 sides it would be a pentagon
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Ellen flipped a coin 80 times. the coin landed heads up 44 times and tails up 36 times. what is the experimental probability of
Vaselesa [24]

Answer:

\frac{9}{20}

Step-by-step explanation:

experimental probability is the probability of an event occuring when we perform an experiment.

It goes according to the results of the experiment, not the theory behind it.

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Hence

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Prove that the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus.
sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

  1. All the sides of the rhombus are congruent:  |DG|\cong |GF| \cong |EF| \cong |DE|
  2. The diagonals are perpendicular

Using the distance formula; d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}

\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}

|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}

\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}

|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}

\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}

|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}

\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}

Using the slope formula; m=\frac{y_2-y_1}{x_2-x_1}

The slope of EG is m_{EG}=\frac{2c-0}{0-0}

\implies m_{EG}=\frac{2c}{0}

The slope of EG is undefined hence it is a vertical line.

The slope of  DF is m_{DF}=\frac{c-c}{a+b-(-a-b)}

\implies m_{DF}=\frac{0}{2a+2b)}=0

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since |DG|\cong |GF| \cong |EF| \cong |DE| and DF \perp FG , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is m_{DE}=\frac{2c-c}{0-(-a-b)}

m_{DE}=\frac{c}{a+b)}

The slope of FG is m_{FG}=\frac{c-0}{a+b-0}

\implies m_{FG}=\frac{c}{a+b}

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The answer would be D because you are subtracting a positive 17 from a positive 88
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