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arsen [322]
3 years ago
15

9(5r-2) and 14r-7 yes or no to tell if this expression is equivalent or not

Mathematics
1 answer:
mixas84 [53]3 years ago
4 0

Answer:

No instead of doing multiplication u did division

Step-by-step explanation:

This equation is called distributive property where u multiply the answer from the outside by the inside number

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If f(x) = 7 + 4x and g (x) = StartFraction 1 Over 2 x EndFraction, what is the value of (StartFraction f Over g EndFraction) (5)
Degger [83]

Answer:

\frac{f}{g}(5) = 270 ⇒ Last answer

Step-by-step explanation:

* If f(x) = 7 + 4x

* If g(x) = \frac{1}{2x}

* We want to find \frac{f}{g}(5)

- Lets find at first \frac{f}{g}(x)

∵ f(x) = 7 + 4x

∵ g(x) = \frac{1}{2x}

∴ \frac{f}{g}(x)=\frac{7+4x}{\frac{1}{2x}}

- Lets divide the numerator by the denominator

∵ The numerator is 7 + 4x

∵ The denominator is \frac{1}{2x}

∴ (7 + 4x) ÷ \frac{1}{2x}

- Lets reverse the division sign to multiplication sign and reciprocal

  the fraction after the division sign

∴ (7 + 4x) × \frac{2x}{1}

∴ \frac{f}{g}(x) = 2x(7 + 4x)

∴ \frac{f}{g}(x) = 14x + 8x²

- Now substitute x by 5

∴  \frac{f}{g}(5) = 14(5) + 8(5)² = 70 + 200 = 270

∴  \frac{f}{g}(5) = 270

4 0
3 years ago
Read 2 more answers
Expand and simplify (2x+5y) (x-3y)
Dmitry [639]
Should be simple:

Let's take this one at a time.

2x(x-3y)

You'd get:
2x^2-3xy
for the first one.

2nd one:
5y(x-3y)
you'd get:
+5xy-3y^2

Put them both together:
2x^2-3xy+5xy-3y^2

Combine like terms.

Your Answer:
2x^2+2xy-3y^2

3 0
3 years ago
There were 756 students enrolled in a freshman-level chemistry class. By the end of the semester, the number of students who pas
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Answer:

4536

Step-by-step explanation:

8 0
2 years ago
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How many unit cubes will fit in the rectangular prism? <br> A) 9 B) 36 C) 40 D) 45
antiseptic1488 [7]

Answer:

D) 45

Step-by-step explanation:

5 x 3 x 3 = 45

8 0
2 years ago
The radius of one circle is three the time radius of another circle. The sum of their areas is 12pi. Find the radius of each cir
zlopas [31]
   
\displaystyle\\&#10;\begin{cases}&#10;R_1 = 3R_2\\&#10;\pi R_1^2 +\pi R_2^2=12\pi ~~~\Big|~~:\pi &#10;\end{cases} \\  \\ &#10;\begin{cases} &#10;R_1 = 3R_2\\&#10;R_1^2 + R_2^2=12 &#10;\end{cases} \\  \\ &#10;(3R_2)^2+ R_2^2=12 \\  \\ &#10;9R_2^2 + R_2^2=12 \\  \\ &#10;10R_2^2=12\\\\&#10;R_2^2 = \frac{12}{10} = \frac{6}{5}  \\  \\ &#10;R_2 =  \boxed{\sqrt{\frac{6}{5}} } \\  \\ &#10;R_1 = \boxed{3\sqrt{\frac{6}{5}} }



7 0
3 years ago
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