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RoseWind [281]
4 years ago
6

What does area mean for a figure

Mathematics
1 answer:
krek1111 [17]4 years ago
8 0
Area is the quantity that expresses the extent of a two-dimensional figure or shape, or planar lamina, in the plane. Surface area is its analog on the two-dimensional surface of a three-dimensional object.

Have a wonderful day
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The absolute value of -1
Vladimir [108]

Answer:

The absolute value of -1 is 1

Step-by-step explanation:

Absolute value is how far a number is from 0 on a number line. Since you can't have a negative amount of spaces, the answer is 1

4 0
3 years ago
(-3y3-5y-2)+(-7y2+5y+2)
Slav-nsk [51]

Answer:

=-23y

Step-by-step explanation:

(-3y3-5y-2)+(-7y2+5y+2)

=-3yX3-5y-2-7yX2+5y+2

=-3X3y-5y-7X2y+5y-2+2

=-3X3y-7X2y-2+2

=-9y-7X2y-2+2

=-9y-14y-2+2

=-23y-2+2

=-23y

I hope this helps!

4 0
3 years ago
Read 2 more answers
a map has a scale of 1 and 1/2 inch equals 16 miles the distance between two parks on the map is 2 and 3/4 inches how far apart
docker41 [41]

Answer:

16 miles   =   x miles

Step-by-step explanation:

this problem involves setting two ratios equal to each other. We call such an equation a proportion.

(1/2) inch      2 3/4 inches

 x = (11/4) * 16 = (11/4) * 2 * 16 = 88 miles

      (1/2)

6 0
3 years ago
Which statement describes a process to solve sqrt b+20 - sqrt b=5?
babunello [35]

Answer:

Step-by-step explanation:

The equation is:

√b+20 - √b = 5

The first step is we will add √b to both sides:

√b+20 -√b +√b = 5 +√b

√b+20 = 5+√b

Now take square at both sides:

(√b+20)^2 = (5+√b)^2

b+20 = 25+10√b+b

Now combine the like terms:

b+20-25-b=10√b

-5 = 10√b

Divide both the terms by 10

-5/10 = 10√b/10

-1/2=√b

Take square at both sides:

(-1/2)^2 = (√b)^2

1/4 = b

So in this type of question we add radical terms to both sides and square both sides twice....

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=Tanx%20%3D%202%2F3" id="TexFormula1" title="Tanx = 2/3" alt="Tanx = 2/3" align="absmiddle" cla
zlopas [31]
The answer for x is 33.69°.
4 0
3 years ago
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