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Dmitry [639]
3 years ago
7

Which statement describes a process to solve sqrt b+20 - sqrt b=5?

Mathematics
1 answer:
babunello [35]3 years ago
7 0

Answer:

Step-by-step explanation:

The equation is:

√b+20 - √b = 5

The first step is we will add √b to both sides:

√b+20 -√b +√b = 5 +√b

√b+20 = 5+√b

Now take square at both sides:

(√b+20)^2 = (5+√b)^2

b+20 = 25+10√b+b

Now combine the like terms:

b+20-25-b=10√b

-5 = 10√b

Divide both the terms by 10

-5/10 = 10√b/10

-1/2=√b

Take square at both sides:

(-1/2)^2 = (√b)^2

1/4 = b

So in this type of question we add radical terms to both sides and square both sides twice....

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Help???????????????????
Reil [10]

Answer:

42:36

=42/36

=(7*6)/(6*6)

=7/6

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What is the value of x?​
morpeh [17]

Answer:

x = 130

Step-by-step explanation:

The sum of the exterior angles of a polygon is always 360

140 + x + 56+ 34 = 360

Combine like terms

230 +x = 360

Subtract 230 from each side

230+x-230 = 360-230

x =130

3 0
3 years ago
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What is the difference between discrete vs continuous data
Sergeeva-Olga [200]
With continuous data, it is possible to find the midpoint of any two distinct values. For instance, if h = height of tree, then its possible to find the middle height of h = 10 and h = 7 (which in this case is h = 8.5)

On the other hand, discrete data can't be treated the same way (eg: if n = number of people, then there is no midpoint between n = 3 and n = 4). 

-------------------------------------

With that in mind, we have the following answers

1) Continuous data. Time values are always continuous. Any two distinct time values can be averaged to find the midpoint

2) Continuous data. Like time values, temperatures can be averaged as well. 

3) Discrete data. Place locations in a race or competition are finite and we can't have midpoints. We can't have a midpoint between 9th and 10th place for instance.

4) Continuous data. We can find the midpoint and it makes sense to do so when it comes to speeds. 

5) Discrete data. This is a finite number and countable. We cannot have 20.5 freshman for instance.
4 0
3 years ago
2. Calculate the energy in joules of a photon whose frequency is 7.55×1014 Hz.
igomit [66]
The energy of a photon is given by
E = h × v

where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴

Substitute 'h' and 'v' into the formula we have

E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon
8 0
3 years ago
Complete the general form equation of the parabola that passes through (4, -11) with vertex at : (2, -3).
fomenos

Answer:

Step-by-step explanation:

You're given a coordinate in the form of (x, y) and you're also given the vertex in the form of (h, k). We will use those in the vertex form of the equation

y=a(x-h)^2+k and solve for a. Filling in:

-11=a(4-2)^2-3 which simplifies a bit to

-11=a(2)^2-3 and a bit more to

-11=4a-3. Add 3 to both sides to get

-8 = 4a so

a = -2

The equation, then, is

y=-2(x-2)^2-3

7 0
3 years ago
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