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3 years ago

Name the numerator and the denominator in each fraction 1 1/2 7/512 12/10 0/78

Mathematics

2 answers:

AnnZ [28]3 years ago

6 0

Numerators:
3
7
12
0
Denominators:
2
512
10
78

Pepsi [2]3 years ago

6 0

Answer: the numerator for the first one is 1. Unless they want you to convert it to 3/2 where the numerator would be 3.

2. 7 is the numerator

3. 12 is the numerator.

4. 0 is the numerator

Step-by-step explanation: The numerator can always be found as the top part of the fraction.

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Y+1=3/4(x+3) in general form pls??

Vikentia [17]

Answer:

Step-by-step explanation:

y+1 =(3/4)x+9/4

y=(3/4)x+1/4

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how do I solve 7v-(2v-16)=5(v+4) please explain if it is a one solution, no solution or infinite solution

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Do the indicated mult. first:

7v - 2v + 16 = 5v + 20
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3 years ago

3) "The difference between twice a number and 17 is no more than 13."*

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Answer:

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Step-by-step explanation:

2x+17 < 13

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3 years ago

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olga2289 [7]

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Step-by-step explanation:

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2 years ago

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Suppose that the functions s and t are defined for all real numbers x as follows.

jeka94

Answer:

$(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39$

Step-by-step explanation:

Given functions are:

$s(x)= x+6\\t(x)= 4x^2$

We have to find:

(s.t)(x) => this means we have to multiply the two functions to get the result.

So,

$(s.t)(x) = s(x)*t(x)\\= (x+6)(4x^2)\\=4x^2.x+4x^2.6\\=4x^3+24x^2$

Also we have to find

(s-t)(x) => we have to subtract function t from function s

$(s-t)(x) = s(x) - t(x)\\= (x+6) - (4x^2)\\=x+6-4x^2$

Also we have to find,

(s+t)(-3) => first we have to find sum of both functions and then put -3 in place of x

$(s+t)(x) = s(x)+t(x)\\= x+6+4x^2$

Putting x = -3

$= -3+6+4(-3)^2\\=-3+6+4(9)\\=3+36\\=39$

Hence,

$(s.t)(x) = 4x^2+24x^2\\(s-t)(x) = x+6-4x^2\\(s+t)(-3) = 39$

8 0

2 years ago