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Romashka [77]
3 years ago
11

Name the numerator and the denominator in each fraction 1 1/2 7/512 12/10 0/78

Mathematics
2 answers:
AnnZ [28]3 years ago
6 0
Numerators:
3
7
12
0
Denominators:
2
512
10
78
Pepsi [2]3 years ago
6 0

Answer: the numerator for the first one is 1. Unless they want you to convert it to 3/2 where the numerator would be 3.

2. 7 is the numerator

3. 12 is the numerator.

4. 0 is the numerator


Step-by-step explanation: The numerator can always be found as the top part of the fraction.


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What is the area of a field that is 132.4m long by 28m wide?
svetlana [45]

Answer:

B

Step-by-step explanation:

its 132.4 times 28

=3707.2

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Which expression does the fraction 3/8 equal to A. 3 times 8 B. 3 divided by eight C. 8 divided by 3 D. 3 - 8
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A fraction bar is division

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Juan has $10. He recently got a job and now makes $9.15 an hour. He now has $760.30. How many hours has he worked?
marissa [1.9K]

Im not sure if im correct but I think the answer is 82 hours.

6 0
3 years ago
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Find the value of :<br><img src="https://tex.z-dn.net/?f=%20%5Csf%20log_%7B3%20%5Csqrt%7B2%7D%20%7D%28324%29%20" id="TexFormula1
qwelly [4]

Answer:

4

Step-by-step explanation:

Is that a log with the base of   3√(2)  ?

If so....my calculator says the answer is   4

Let's see if we can do it w/ou the calculator:

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x log (3 sqrt 2)  =   log (3^4 *2^2)  =  4 log ( 3 * 2^(2/4)) = 4 log (3 sqrt2)

                       now divide both sides by log (3 sqrt2 )

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8 0
2 years ago
PLEASE HELP!!!! WILL MARK BRAINLIEST!!!!
irga5000 [103]

Answer:

None of these.

Step-by-step explanation:

Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem.  So we know (x-6) is not a factor because the remainder wasn't zero.

Let's assume we are trying to figure out if (x^2+6) is a factor.  The quotient is (x-6) and the remainder is 13 according to the problem.  So we know (x^2+6) is not a factor because the remainder wasn't zero.

In order for 13 to be a factor of P, all the terms of P must be divisible by 13.  That just means you can reduce it to a form that is not a fraction.

If we look at the first term x^3 and we divide it by 13 we get \frac{x^3}{13} we cannot reduce it so it is not a fraction so 13 is not a factor of P

None of these is the right option.

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3 years ago
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