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ANEK [815]
3 years ago
15

A train leaves little rock Arkansas, travels north at 85 kilometers per hour. another train leaves same time and travels south a

t 80 kilometers per hour. How long will it take before they are 495 kilometers apart
Mathematics
1 answer:
iragen [17]3 years ago
6 0

Hi,

Let us denote first train with T₁, its distance d₁, its speed v₁ = 85 km/h.

Similarly, second train would be with T₂, its distance d₂, its speed v₂ = 80 km/h. Also, let d be total distance, d = 495 km.

Given being the fact that train T₁ travels north, and train T₂ travels south, their path is on a straight vertical line. Please create a simple drawing, you will see the vertical line immediately.

Then, we need to find the time t, when d₁ + d₂ = d = 495 km (1)

Each speed v₁, and v₂ is constant, therefore we apply very well known formula:

d₁ = v₁·t, and d₂ = v₂·t (2).

From (1) and (2) we have:

v₁·t + v₂·t = d, or (v₁ + v₂)t = d ⇒ t = d/(v₁ + v₂) = 495/(80 + 85) = 495/165 = 3 hours.

So, it takes 3 hours to have those 2 trains 495 km apart.

Green eyes.

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