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irakobra [83]
4 years ago
12

Rachael bought 4 shirts and some number of pants. Write an expression to show how many pieces of clothing she bought

Mathematics
1 answer:
Gekata [30.6K]4 years ago
7 0
4+n=x
I think this should work but I'm not really sure..
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8 0
3 years ago
A. Plot 13.58 on a number line on which the long
Lerok [7]

Answer:

Se attached for plots and here is position of the numbers:

a. Plot 13.58 on a number line on which the long

tick marks are whole numbers.

  • 13 < 13.58 < 14

b. Plot 0.193 on a number line on which the long

tick marks are tenths.

  • 0.1 < 0.193 < 0.2

c. Plot 26.9999 on a number line on which the

long tick marks are thousandths.

  • 26.999 < 26.9999 < 27.000

4 0
3 years ago
In order to have 6,000,000 in 40 years with a 5.75% rate. how much should be deposited each month?
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

This is an Annuity question. It is asking for recurring monthly payment(PMT).  <em>You can use a financial calculator to solve it. I am using (Texas Instruments BA II plus)</em>

Since the payments occur monthly , adjust the interest rate to monthly rate and multiply  40 years by 12 since we have 12 months in a  year<em>.</em>

Total duration of investment ; N = 40*12 = 480

Interest rate; I/Y = 5.75% /12 = 0.4792%

Future value; FV = 6,000,000

Present value ; PV = 0

then CPT PMT = 3,222.912

Therefore $3,222.91  should be deposited each month to achieve the goal.

4 0
3 years ago
Can someone please explain how to do this!!!
DedPeter [7]

Hi there!

So we are given that:-

  • tan theta = 7/24 and is on the third Quadrant.

In the third Quadrant or Quadrant III, sine and cosine both are negative, which makes tangent positive.

Since we want to find the value of cos theta. cos must be less than 0 or in negative.

To find cos theta, we can either use the trigonometric identity or Pythagorean Theorem. Here, I will demonstrate two ways to find cos.

<u>U</u><u>s</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>I</u><u>d</u><u>e</u><u>n</u><u>t</u><u>i</u><u>t</u><u>y</u>

\large \displaystyle{ {tan}^{2}  \theta + 1 =  {sec}^{2}  \theta}

Substitute tan theta = 7/24 in.

\large \displaystyle{ {(  \frac{7}{24}) }^{2}  + 1 =  {sec}^{2} \theta }

Evaluate.

\large \displaystyle{ \frac{49}{576}  + 1 =  {sec}^{2}  \theta} \\  \large \displaystyle{ \frac{625}{576}  =  {sec}^{2}  \theta}

Reminder -:

\large \displaystyle{ sec \theta =  \frac{1}{cos \theta} }

Hence,

\large \displaystyle{ \frac{576}{625}  =  {cos}^{2}  \theta} \\  \large \displaystyle{ \sqrt{ \frac{576}{625} }  = cos  \theta} \\  \large \displaystyle{ \frac{24}{25}  = cos \theta}

Because in QIII, cos<0. Hence,

\large \displaystyle \boxed{ \blue{cos \theta =  -  \frac{24}{25} }}

<u>U</u><u>s</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>P</u><u>y</u><u>t</u><u>h</u><u>a</u><u>g</u><u>o</u><u>r</u><u>e</u><u>a</u><u>n</u><u> </u><u>T</u><u>h</u><u>e</u><u>o</u><u>r</u><u>e</u><u>m</u>

\large \displaystyle{ {a}^{2}  +  {b}^{2}  =  {c}^{2} }

Define c as our hypotenuse while a or b can be adjacent or opposite.

Because tan theta = opposite/adjacent. Therefore:-

\large \displaystyle{ {7}^{2}  +  {24}^{2}  =  {c}^{2} } \\  \large \displaystyle{49 + 576 =  {c}^{2} } \\  \large \displaystyle{625 =  {c}^{2} } \\  \large \displaystyle{25 = c}

Thus, the hypotenuse side is 25. Using the cosine ratio:-

\large \displaystyle{cos \theta =  \frac{adjacent}{hypotenuse}}

Therefore:-

\large \displaystyle{cos \theta =  \frac{24}{25} }

Because cos<0 in Q3.

\large \displaystyle \boxed{ \red{cos \theta =  -  \frac{24}{25} }}

Hence, the value of cos theta is -24/25.

Let me know if you have any questions!

8 0
3 years ago
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