Tan⁴x - sec⁴x = 1 - 2sec²x
tan²x = sec²x - 1
tan⁴x - sec⁴x = 1 - 2sec²x
(tan²x)² - sec⁴x = 1 - 2sec²x
(sec²x - 1)² - sec⁴x = 1 - 2sec²x
(sec²x)² - 2 * sec²x + 1 - sec⁴x = 1 - 2sec²x
sec⁴x - 2 sec²x + 1 - sec⁴x = 1 - 2sec²x
sec⁴x can be cancelled:
- 2 sec²x + 1 = 1 - 2sec²x
1 - 2sec²x = 1 - 2sec²x
Answer:
Weight of dog: 34 pounds,
Weight of cat: 12 pounds.
Step-by-step explanation:
Let d represent weight of dog and c represent weight of cat.
We have been given that a dog weighs two pounds less than three times the weight of a cat.
3 times weight of cat: 
We can represent the given information in an equation as:

We are also told that the dog also weights twenty-two more pounds than the cat. We can represent the given information in an equation as:

Equate both equations:






Therefore, the weight of cat is 12 pounds.
Substitute
in equation (2)



Therefore, the weight of dog is 34 pounds.
Answer: The function that models the distance they drive is
f(x) = 50x + 20 where x is the time in hours
reasonable domain: 0 ≤ x ≤ 3
Step-by-step explanation:
examples:
95 = 50(1.5) + 20 After driving another hour and a half, they will have driven a total of 95 miles.
120 = 50(2) + 20 This means that after 2 more hours they will reach their destination.
There is a little ambiguity in the question. The function could be written as if they are starting out. f(x) = 50t
20 = 50(.4) At 50 mph it took .4 hours to go 20 miles.
120 = 5(2.4) The whole trip took 2.4 hours.
3 periods....20 minutes each.....3 * 20 = 60 total minutes playing time
colin plays 12 minutes each period...12 * 3 = 36 minutes
Collins playing time to total playing time = 36/60 reduces to 9/15 or 9:15 or 9 to 15 <===
Answer:
Always true
Step-by-step explanation:
Given

Required
Determine its type of solution

Collect Like Terms

Take LCM


Multiply both sides by 



<em>Hence, the equation is always true for x = 3</em>