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stepladder [879]
2 years ago
15

A square pyramid has a base side length of 20.4cm and a height of 18.2cm which square pyramid is similar

Mathematics
1 answer:
Maksim231197 [3]2 years ago
7 0

Answer:

C) base side length = 30.6 cm, height = 27.3 cm

Step-by-step explanation:

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Find the unknown side length of the rectangle if its area is 11m 2.<br> 3 m<br> ?<br> 11 m
dexar [7]

Answer:

the side length is 3.

Step-by-step explanation:

you would do 11/3 2/3

and you would get 3

4 0
3 years ago
If T is the midpoint of SU find the values of x, ST and SU.
Nitella [24]

Answer:  The required values are

x = 12 units, ST = 60 units and SU = 120 units.

Step-by-step explanation:  Given that T is the midpoint of SU, where

ST = 5x  and  TU = 3x + 24.

We are to find the values of x, ST and SU.

Since T is the midpoint of SU, so we get

ST=TU\\\\\Rightarrow 5x=3x+24\\\\\Rightarrow 5x-3x=24\\\\\Rightarrow 2x=24\\\\\Rightarrow x=\dfrac{24}{2}\\\\\Rightarrow x=12.

So, the value of x is 12.

Therefore,

ST=5\times12=60

and

SU=5x+3x+24=8x+24=8\times12+24=96+24=120.

Thus, the required values are

x = 12 units, ST = 60 units and SU = 120 units.

8 0
2 years ago
Read 2 more answers
Which of the following is the solution to the system of equations shown below?
antiseptic1488 [7]

Answer:

x = -2, x = 1

Step-by-step explanation:

mark as brainliest it is right

3 0
2 years ago
A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one
d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855

The probability  that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0
3 years ago
Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x
iren [92.7K]

Answer:

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

Step-by-step explanation:

One is asked to find the root of the following equation:

2x^2+1=5x

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

ax^2+bx+c=0

Change the given equation using inverse operations,

2x^2+1=5x

2x^2-5x+1=0

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

Simplify,

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

\frac{5(+-)\sqrt{25-8}}{4}

\frac{5(+-)\sqrt{17}}{4}

Rewrite,

\frac{5(+-)\sqrt{17}}{4}

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

8 0
3 years ago
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