School x and school y play each other in a competition. School X has 8 more points than school Y. School X has 3 times as many p
2 answers:
Answer:
Let the points for School X be a
and for the School Y be b.
From the given condition : School X has 8 more points than school Y.
we have;
a = b+8 ......[1]
Also, School X has 3 times as many points as school Y, which implies
a = 3b ......[2]
Substitute the value a of [2] in [1]; to solve for b;
we have;
3b=b+8
Subtract b from both sides of an equation we get;
3b-b=b+8-b
Simplify:
2b=8
Divide by 2 from both sides of an equation we get;
Simplify:
b=4
Substitute the value of b in equation [2];
Therefore, School X has 12 points and School Y has 4 points.
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Answer: 11 is the required number that always divides such differences for the following types of numbers.
Step-by-step explanation:
Take any 3 - digit number, say, 325
On reversing its digit it becomes, 523
On subtracting the smaller of the two numbers from the larger,
we can see that 198 is an even number.
take another number say, 629
On reversing its digit, it becomes = 926
On subtracting , we get that
But 297 is not an even number.
But there is one common in both the cases is that both the differences are divisible by 11.
Hence, 11 is the required number that always divides such differences for the following types of numbers.