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2 years ago

Is PRB congruent to QSB? Justify your answer.

Mathematics

1 answer:

Serhud [2]2 years ago

8 0

Answer:

When looking at this model, and asking yourself the question, is PRB congruent to QSB? PRB is in fact congruent to QSB. Congruent means that two figures have the same shape/size, no matter if it's mirrioring or not it is congruent. In this image, PRB is one shape, and QSB is another. They have the exact same points and they're also the same shape, but one is flipped the right side up. It was also stated PQ and RS bisect eachother at point B, <p is congruent to <Q, and <R is congruent to <S proving all these connections make this figure conguent.

Step-by-step explanation:

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3 years ago

A particle moves on a straight line and has acceleration a(t)=24t+2. Its position at time t=0 is s(0)=3 and its velocity at time

user100 [1]

Answer:

It's position at time t = 5 is 593.

Step-by-step explanation:

The velocity v(t) is the integral of the acceleration a(t)

The position s(t) is the integral of the velocity v(t)

We have that:

The acceleration is:

$a(t) = 24t + 2$

Velocity:

$v(t) = \int {a(t)} \, dt = \int {24t + 2} \, dt = 12t^{2} + 2t + K$

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13

Then

$v(t) = 12t^{2} + 2t + 13$

Position:

$s(t) = \int {s(t)} \, dt = \int {12t^{2} + 2t + 13} \, dt = 4t^{3} + t^{2} + 13t + K$

Since s(0) = 3

$s(t) = 4t^{3} + t^{2} + 13t + 3$

What is its position at time t=5?

This is s(5).

$s(t) = 4t^{3} + t^{2} + 13t + 3$

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$s(5) = 593$

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Answer:

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Step-by-step explanation:

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