All categories

3 years ago

The default horizontal alignment in Word is

Mathematics

1 answer:

Irina18 [472]3 years ago

6 0

Answer:

i believe it is left aligned

Step-by-step explanation:

i hope it is correct if there is any wrong i will be glad to say for me :)

You might be interested in

ASAP PLEASE HELP ILL MARK AS BRAINLIEST IN TALKING FAST

pav-90 [236]

Answer:

4 , 24 , 144 , 864 , 5184

This is a sequence which is multiplied by 6 with the new digit.

First: 4

second: 4 * 6 = 24

third: 24 * 6 = 144

fourth: 144 * 6 = 864

fifth: 864* 6 = 5184

sixth: 5184 * 6 = 31104

seventh: 31104 * 6 = 186624

This sequence is never ending. Write the first 5 five in sequence that's the answer.

5 0

2 years ago

Please help with this. I don’t understand what I’m doing. It’s due tonight

Sunny_sXe [5.5K]

Answer:

.0006

Step-by-step explanation:

I'm not sure if this is correct.. sorry if this is wrong.. :(

3 0

2 years ago

(Maths) question: a bag of lollies contain 36 lollies, the lollies are shared evenly between 9 children, let ‘t’ represent the n

BabaBlast [244]

Answer:

you got this bro

Step-by-step explanation:

stay calm and dont over think about it you are smart just take your time

3 0

4 years ago

Ethan thinks that 5(13) can be found by adding 50+15

Mumz [18]

He is correct because if you break 13 up into 10 and 3 and you multiply them individually you get 50 and 15 you then add the and you get 65

4 0

4 years ago

Read 2 more answers

A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte

ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, $q_1 = Q- r \times Q$

$q_1 = Q(1-r)\cdots(i)$

The value of quantity after 2 months, $q_2 = q_1- r \times q_1$

$q_2 = q_1(1-r)$

From equation (i)

$q_2=Q(1-r)(1-r) \\\\q_2=Q(1-r)^2\cdots(ii)$

The value of quantity after 3 months, $q_3 = q_2- r \times q_2$

$q_3 = q_2(1-r)$

From equation (ii)

$q_3=Q(1-r)^2(1-r)$

$q_3=Q(1-r)^3$

Similarly, the value of quantity after n months,

$q_n= Q(1- r)^n$

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

$q_{48}=Q(1-r)^{48}$

Putting Q=6200 and r=5.5%=0.055, we have

$q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32$

Hence, the value of quantity after 4 years is 410.32.

4 0

3 years ago

Read 2 more answers